You may need to use the appropriate appendix table to answer this question.Suppose that the mean daily viewing time of television is 8.35 hours. Use a normal probability distribution with a standard deviation of 2.5 hours to answer the following questions about dailytelevision viewing per household(a) What is the probability that a household views television between 4 and 11 hours a day? (Round your answer to four decimal places.)(b) How many hours of television viewing must a household have in order to be in the top 4% of all television viewing households? (Round your answer to two decimal places.)hrs(c) What is the probability that a household views television more than 5 hours a day? (Round your answer to four decimal places.)

Given information- Population Mean, µ = 8.35 hours Population standard deviation, σ = 2.5 hours Let…

Answered: Suppose that the mean daily viewing…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Assume that the traffic to the web site of Smiley's People, Inc., which sells customized T-shirts, follows a normal distribution, with a mean of 6.5 million visitors per day and a standard deviation of 3 million visitors per day. What is the probability that the web site has more than 1.5 million visitors in a single day? Question 3 options: 0.7545 0.5543 0.9522 0.3454
The weekly earnings of shift supervisors in the glass industry follow a normal probability distribution with a mean of $1,000 and a standard deviation of $100. What is the z value of income X of a supervisor who earns $1,100 per week? What about a supervisor who makes $900 a week?
Television viewing reached a new high when the global information and measurement company reported a mean daily viewing time of 7.56 hours per household. Use a normal probability distribution with a standard deviation of 2.8 hours to answer the following questions about daily television viewing per household. 3 € 4 st a. What is the probability that a household views television e between 4 and 8 hours a day (to 4 decimals)? 3 A 4 1 t 1 1 # 1 문 £ $ Ž £ # 1 1 B 1 1 I 1
Customers stay on average 16 minutes in line before they can get into a certain store. The standard deviation is 4 minutes, and you should assume this normally distributed. a. Find the probability that a randomly picked individual will wait between 10 and 20 minutes. b. What proportion of waiting time falls above 24 min or below 6 min?
The following data represent a portion of quarterly net sales (in $ millions) of Lowe's Companies, Inc., over five years. Net Sales 8861 10169 1 9984 Source: All data retrieved from Annual Reports for Lowe's Companies, Inc. Click here for the Excel Data File a-1. Estimate an exponential trend model with seasonal dummy variables. (Round your answers to 4 decimal places.) Year 2004 2004 2008 Intercept d1 d2 d3 t Variable Quarter 1 2 1 1 Se Exponential Trend A 1 Year 2 2004 3 2004 4 2004 5 2004 6 2005 7 2005 8 2005 9 2005 10 2006 11 2006 12 2006 13 2006 14 2007 15 2007 16 17 2007 2007 2008 18 19 2008 2008 20 21 2008 B Quarter 123-AWNA W NAWN-AW23 4 4 3 4 4 4 C Net Sales 8861 10169 9064 8550 9913 11929 10592 10808 11921 13389 11211 10406 12172 14167 11565 10379 12009 14509 11728 9984
The probabilities that a customer buys 1, 2, 3, 5, 8 apples each day in a grocery store are 0.20, 0.32, 0.23, 0.18, 0.07 respectively. Let B be the number of apples a customer buys in a day. What is the standard deviation?
Television viewing reached a new high when the global information and measurement company reported a mean daily viewing time of 8.35 hours per household. Use a normal probability distribution with a standard deviation of 2.5 hours to answer the following questions about daily television viewing per household. a. What is the probability that a household views television between 6 and 10 hours a day (to 4 decimals)? b. How many hours of television viewing must a household have in order to be in the top 4% of all television viewing households (to 2 decimals)? hours c. What is the probability that a household views television more than 5 hours a day (to 4 decimals)? 0.9099
One year consumers spent an average of $22 on a meal at a resturant. Assume that the amount spent on a resturant meal is normally distributed and that the standard deviation is $3.Complete parts (a) through (c) below. a. What is the probability that a randomly selected person spent more than $24?
According to a certain website, the average daily time spent on social networking by internet users worldwide is 145 minutes. Assume the standard deviation is 45 minutes and that the probability distribution is normal. What is the probability that a randomly selected person spends daily at least 3 hours on social networking? Select one: a. 0.7794 O b. 0.2206 c. 0.7823 O d. 0.2177
Assume that the sales of Teri’s Specialty Cakes has historically followed a normal distribution, with an average of 250 cakes per month, and a standard deviation of 15 cakes.a. What is the probability that the sales for cakes will be no more than 285 over the next month?b. What is the probability that the sales for the cakes will be no more than 230 cakes over the next month?c. What is the probability that the sales for the cakes will be between 245 and 265 over the next month?d. What number of cake demand can Teri reasonably assume with a confidence level of 95%?For a, b, c, and d, please write out your work for at least one of these problems. For all problems, explain your answers and sketch a plot (similar to the handouts and text).
Solve for (E)
Workers' Distractions. A recent study showed that the modern working person experiences an average of 2.1 hours per day of distractions (phone calls, e- mails, impromptu visits, etc.). A random sample of 16 workers for a large corporation found that these workers were distracted an average of 1.8 hours per day and the standard deviation was 20 minutes. Estimate the true mean population distraction time with 90% confidence, and compare your answer to the results of the study. (1.654,1.946). Mean of the study is outside or "different" from the result of our study.

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