Suppose that the length of long distance phone calls, measured in minutes, is known to have an exponential distribution with the average length of a call equal to $10 minutes. a. The lambda of this distribution is 0.1 b. The probability that the length of a phone call is longer than 12 is P(x 2 12) = 0.3011942' c. The probability that the length of a phone call is shorter than 5 is P(x s 5) = 0.3934693 d. The probability that the length of a phone call is between 8 and 14 is P(8 s x s 14) = 0.86 e. The 86th percentile is a phone call that lasts 19.66 X minutes.

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Suppose that the length of long distance phone calls, measured in minutes, is known to have an
exponential distribution with the average length of a call equal to $10 minutes.
a. The lambda of this distribution is 0.1
b. The probability that the length of a phone call is longer than 12 is P(x 2 12) = 0.3011942 .
c. The probability that the length of a phone call is shorter than 5 is P(x < 5) = 0.3934693
d. The probability that the length of a phone call is between 8 and 14 is P(8 s x s 14) =
0.86
e. The 86th percentile is a phone call that lasts 19.66
x minutes.
Transcribed Image Text:Suppose that the length of long distance phone calls, measured in minutes, is known to have an exponential distribution with the average length of a call equal to $10 minutes. a. The lambda of this distribution is 0.1 b. The probability that the length of a phone call is longer than 12 is P(x 2 12) = 0.3011942 . c. The probability that the length of a phone call is shorter than 5 is P(x < 5) = 0.3934693 d. The probability that the length of a phone call is between 8 and 14 is P(8 s x s 14) = 0.86 e. The 86th percentile is a phone call that lasts 19.66 x minutes.
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