Suppose that the insurance companies did do a survey. They are interested inthe population proportion of drivers who claim they always buckle up with 95%confidence. Their estimate must be accurate within 2% of the true proportion.i.If no preliminary estimate is available, find the minimum sample sizerequired.ii. Find the minimum sample size needed if they randomly surveyed 400drivers and found that 320 claimed they always buckle up.

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Answered: Suppose that the insurance companies…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Prof. Jacob wants to know, with 90% confidence, the proportion of students who like to eat in the cafeteria. A previous survey showed that 62% like to eat in the cafeteria. Prof. Jacob likes to be accurate with an error of 0.025 of its true proportion. What sample size does Prof. Jacob need?* A. 1,020 B. 1,020.06 C. 1,021 D. 1,022
The average worker at a local brake manufacturer produces 10 brakes per day (other statistical information was not known). An industrial psychologist was hired to increase worker productivity and a new assembly method was designed and tested in a sample of workers. Identify the appropriate test. Select one: a. independent samples t test b. z test c. single sample t test d. paired samples t test
In the population of students at Milpitas High School, the proportion who are in the marching band is 0.10. In a random sample of 100 students from this population, the proportion who are in the marching band is 0.04. We would call the value 0.04 a A. statistic. B. parameter. C. z-score. D. P-value. E. significance level.
A poll found that 59% of a sample of 1020 teens in a certain large country go online several times a day. (Treat this sample as a simple random sample.) Complete parts a through e below. Find the margin of error for this poll if we want 90% confidence in our estimate of the percent of teens in the country who go online several times a day. Explain what the margin of error means. If instead we need to be 95% confident, will the margin of error be larger or smaller? Explain. Find that margin of error.
You decide that you want to make sure your estimate from part a is correct. You go out and gather 10 simple random samples of 25 people in your school and calculate the proportion of students within each sample whose Amazon packages arrive within two business days of ordering. The proportion of customers that receive their packages within two days of ordering are given below. 0.70, 0.75, 0.6, 0.95, 0.90, 0.73, 0.87, 0.86, 0.92, 0.97 Explain why all of the sample proportions are not the same.
One cable company advertises that it has excellent customer service. In fact, the company advertises that a technician will be there within 30 minutes of when a service call is placed. One frustrated customer believes this is not the truth, claiming that it takes over 30 minutes for the cable repairman to arrive. The customer asks 15 of his neighbors how long it has taken for the cable repairman to arrive when they have called for him. The sample mean for this group is 32.2 minutes with a sample standard deviation of 3.6 minutes. Test the customer’s claim at the 0.02 level of significance. (a) State the null and alternative hypotheses (b) Find the value of your test statistic. Draw a picture and label its location on the normal curve. Also shade the area where you will find the p-value. (c) Calculate the p-value from the sample data. Compare it to the significance level. Label it’s value and location on your bell curve (d) Write a full…
Data analysts prefer to deal with random sampling error rather than statistical bias because A. All data analysts are fair people B. There is no statistical method for managing statistical bias C. They do not want to be accused of being biased in today's society D. Random sampling error makes their work more satisfying E. All of the above F. None of the above
A researcher wants to estimate the mean income of a population with a 95% confidence level and a margin of error of $100. How large should the sample size be for the estimation?
Suppose the percentage of married couples who own a home is 33% for a given population. What is the standard error of the sampling distribution of proportions for the sample sizes n = 200, n = 300, and n = 400?
Use the data and table below to test the indicated claim about the means of two paired populations (matched pairs). Assume that the two samples are each simple random samples selected from normally distributed populations. Make sure you identify all values. The table below shows the blood glucose of 20 students before breakfast and two hours after breakfast, using a specific insulin dosing formula to cover carbohydrates. Is there compelling statistical evidence that the specific insulin dosing formula is effective in reducing blood glucose levels? Use a significance level of 0.05. We have the differences (gain or loss), but we still need to compute the mean, standard deviation, and know the sample size for the differences (use Excel or Sheets for this computation). Once those are found, we can apply methods that are used for a 1 sample t-test. Student Before Meal After Meal Difference 1 161 114 -47 2 196 88 -108 3 132 80 -52 4 175 96 -79 5 169 112 -57 6 138 137…
Select the most appropriate answer. The estimation of the population average age of registered voters in the state of Ohio based on the sample average age of 1,000 registered voters in that state and its corresponding margin of error is an example of O descriptive statistics. O deductive statistics. O inferential statistics. O a statistic. a parameter.
The average spent nationally on Christmas gifts in 2020 was reported to be $650 per person. Below is a random sample of gift givers from Iowa and what they spent in 2020. Is there sufficient evidence to conclude that Iowans spend less than the national average? Estimate the average amount spent by Iowans on Christmas gifts in 2020 with a 90%-CI. 700 450 400 525 550 550 600 575 650 625 500

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