Chapter3: Functions
Section3.1: Functions And Function Notation
Problem 92SE: Show that the function f(x)=3(x5)2+7 is not one-to-one.
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Question
![Suppose that the function h is defined on the interval (-2, 2] as follows.
if-2<x≤-1
if - 1<x≤0
if 0<x<1
if 1<x<2
Find h(-1), h (0.75), and h (2).
h(x)=
-1
0
1
2
h(-1) = 0
h (0.75) =
h (2) = 0
00
X](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F2039606c-ddf8-4dfc-99c4-5a13e28c47b4%2Fc7c3271c-08ba-4043-8c87-58989790879f%2Fyzxxez_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Suppose that the function h is defined on the interval (-2, 2] as follows.
if-2<x≤-1
if - 1<x≤0
if 0<x<1
if 1<x<2
Find h(-1), h (0.75), and h (2).
h(x)=
-1
0
1
2
h(-1) = 0
h (0.75) =
h (2) = 0
00
X
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