Suppose that the function g is defined, for all real numbers, as follows. if x+0 -1 g(x) = -2 if x= 0 Graph the function g.

Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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The text on the screen is as follows:

---

"Suppose that the function \( g \) is defined, for all real numbers, as follows.

\[
g(x) = 
\begin{cases} 
-1 & \text{if } x \neq 0 \\
-2 & \text{if } x = 0 
\end{cases}
\]

Graph the function \( g \)."

---

Below the text, there is a coordinate plane with the x-axis and y-axis. The graph is expected to represent the function \( g(x) \) as defined above. 

Explanation of the graph:
- For all values of \( x \) not equal to 0, \( g(x) = -1 \). This means the graph will have a horizontal line at \( y = -1 \) for \( x \neq 0 \).
- At \( x = 0 \), \( g(x) = -2 \). Therefore, there will be a distinct point at \( (0, -2) \).
- The graph will show a continuous line at \( y = -1 \) with an isolated point at \( (0, -2) \).

To visually distinguish \( x = 0 \), you might see a filled or open circle on the graph to represent the change in value.
Transcribed Image Text:The text on the screen is as follows: --- "Suppose that the function \( g \) is defined, for all real numbers, as follows. \[ g(x) = \begin{cases} -1 & \text{if } x \neq 0 \\ -2 & \text{if } x = 0 \end{cases} \] Graph the function \( g \)." --- Below the text, there is a coordinate plane with the x-axis and y-axis. The graph is expected to represent the function \( g(x) \) as defined above. Explanation of the graph: - For all values of \( x \) not equal to 0, \( g(x) = -1 \). This means the graph will have a horizontal line at \( y = -1 \) for \( x \neq 0 \). - At \( x = 0 \), \( g(x) = -2 \). Therefore, there will be a distinct point at \( (0, -2) \). - The graph will show a continuous line at \( y = -1 \) with an isolated point at \( (0, -2) \). To visually distinguish \( x = 0 \), you might see a filled or open circle on the graph to represent the change in value.
The problem statement is as follows:

Suppose that the function \( f \) is defined for all real numbers as follows:

\[
f(x) = 
\begin{cases} 
1 - x^2 & \text{if} \ x < 1 \\ 
-2x - 3 & \text{if} \ x \geq 1 
\end{cases}
\]

You are asked to graph the function \( f \). Then determine whether or not the function is continuous.

### Explanation of the Graph:

The graph on the screen appears to consist of two parts:

1. **Quadratic Function**: \( f(x) = 1 - x^2 \) for \( x < 1 \)
   - This portion of the graph is part of a downward opening parabola. It will have its vertex at the point (0, 1) and crosses the x-axis at x = ±1. Only the section for \( x < 1 \) is relevant here.

2. **Linear Function**: \( f(x) = -2x - 3 \) for \( x \geq 1 \)
   - This part of the graph is a straight line with a negative slope. It passes through the point (1, -5) and continues downward.

You should evaluate the function at \( x = 1 \) to determine continuity:
- From the left (using \( 1 - x^2 \)), \( f(1^{-}) = 1 - 1^2 = 0 \)
- From the right (using \(-2x - 3\)), \( f(1^{+}) = -2(1) - 3 = -5 \)

Since the limits from the left and right do not match, the function is discontinuous at \( x = 1 \).

The screen also includes graphing tools, such as line, curve, and point selectors, indicating that you can use these to construct the graph visually.
Transcribed Image Text:The problem statement is as follows: Suppose that the function \( f \) is defined for all real numbers as follows: \[ f(x) = \begin{cases} 1 - x^2 & \text{if} \ x < 1 \\ -2x - 3 & \text{if} \ x \geq 1 \end{cases} \] You are asked to graph the function \( f \). Then determine whether or not the function is continuous. ### Explanation of the Graph: The graph on the screen appears to consist of two parts: 1. **Quadratic Function**: \( f(x) = 1 - x^2 \) for \( x < 1 \) - This portion of the graph is part of a downward opening parabola. It will have its vertex at the point (0, 1) and crosses the x-axis at x = ±1. Only the section for \( x < 1 \) is relevant here. 2. **Linear Function**: \( f(x) = -2x - 3 \) for \( x \geq 1 \) - This part of the graph is a straight line with a negative slope. It passes through the point (1, -5) and continues downward. You should evaluate the function at \( x = 1 \) to determine continuity: - From the left (using \( 1 - x^2 \)), \( f(1^{-}) = 1 - 1^2 = 0 \) - From the right (using \(-2x - 3\)), \( f(1^{+}) = -2(1) - 3 = -5 \) Since the limits from the left and right do not match, the function is discontinuous at \( x = 1 \). The screen also includes graphing tools, such as line, curve, and point selectors, indicating that you can use these to construct the graph visually.
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