Suppose that the average and standard deviation of the fine for speeding on aparticular highway are 111.12 and 13.04, respectively. Calculate an interval that issymmetric around the mean such that it contains approximately 68% of fines.Assume that the fine amount has a normal distribution.1) (111.12, 13.04)2) (98.08, 124.16)3) (124.16, 98.08)4) (85.04, 137.2)5) (137.2, 85.04)

The Normal distribution is also called as the Gaussian distribution. It is the most common…

Answered: Suppose that the average and standard…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Assume that thermometer readings are normally distributed with a mean of 0°C and a standard deviation of 1.00°C. A thermometer is randomly selected and tested. For the case below, draw a sketch, and find the probability of the reading. (The given values are in Celsius degrees.) Between 1.00 and 2.25 Draw a sketch. Choose the correct graph below.
Use the formula to find the standard error of the distribution of differences in sample means, x⎯⎯1−x⎯⎯2x¯1-x¯2.Samples of size 40 from Population 1 with mean 3.7 and standard deviation 1.9 and samples of size 40 from Population 2 with mean 1.9 and standard deviation 1.2Round your answer for the standard error to two decimal places.standard error = Enter your answer in accordance to the question statement
Q.4
Q2. Calculate Standard Deviation, Variance and Co-efficient of variation Weight (Kg) No. of Residents 10-20 100 20-30 85 30-40 125 40-50 20 50-60 30 60-70 5 70-80
Assume that ﬁnal exam scores in a given course are approximately normally distributed with a mean of 75 and a standard deviation of 10 points. In a class of 200 students, how many would you expect to fail the exam (i.e., score less than 60) (note: scores can only be approximately normally distributed, because the minimum score is 0, but this should not alter the answer, given how large the mean is relative to the standard deviation).
8.50 D
Assume the data set described is normally distributed with the given mean and standard deviation, and with n total values. Find the approximate number of data values that will fall in the given range. Mean-8 Standard deviation-1.5 n-45 Range: 6.5 to 9.5 In this case, we expect about 52 data values to fall between 6.5 and 9.5.
Chebyshev's Theorem states that for any distribution of numerical data, at least 1-1/k? of the numbers lie within The percent of numbers between 88 and 112 is at least %. k standard deviations of the mean. (Round to the nearest hundredth as needed.) In a certain distribution of numbers, the mean is 100, with a standard deviation of 6. Use Chebyshev's Theorem to tell what percent of the numbers are between 88 and 112.
Assume that adults have IQ scores that are normally distributed with a mean of 104.7 and a standard deviation of 24.1. Find the probability that a randomly selected adult has an IQ greater than 137.1. (Hint: Draw a graph.) The probability that a randomly selected adult from this group has an IQ greater than 137.1 is (Round to four decimal places as needed.)
John's answering machine receives about 6 telephone calls between 8:00 am and 8:00 pm. Let X = the number of phone calls received between 1:00 pm to 5:00 pm. What is the standard deviation of X?
Assume that the readings at freezing on a batch of thermometers are normally distributed with a mean of 0°C and a standard deviation of 1.00°C. A single thermometer is randomly selected and tested. Let Z represent the reading of this thermometer at freezing. What reading separates the highest 46.73% from the rest? That is, if P(z > c) = 0.4673, find c. c = °C
Assume that a randomly selected subject is given a bone density test. Bone density test scores are normally distributed with a mean of 0 and a standard deviation of 1. Draw a graph and find Upper P 10 ,the 10 th percentile. This is the bone density score separating the bottom 10% from the top 90%. a. The bone density score corresponding to Upper P 10 is (Round to two decimal places as needed.)

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