Suppose that Po is invested in a savings account in which interest is compounded continuously at 6.5% per year. That is, the balance P grows at the rate given by the following equation. dP = 0.065P(t) dt (a)Find the function P(t) that satisfies the equation. Write it in terms of Po and 0.065. (b)Suppose that $1000 is invested. What is the balance after 2 years? (c)When will an investment of $1000 double itself? (a) Choose the correct answer below. O A. P(1) = Po e0 065t O B. P) = PO) e0 065t OC. Po = P(1) e0 0651 O D. P)=0.065Poe (b) The balance after 2 year is $ (Type an integer or decimal rounded to two decimal places as needed) (c) The doubling time is year.

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