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Suppose that λ =A₁, A₂ are constants such that u(z,y) = F (z+ Ay) statisfied the PDE 82 -4 ( 5²2 U (2, 3)) + 3,²2 u (x, y) = 0 dy2 for any twice-differentiable function of one variable F(s). Suppose also that X₁ <₂, enter the values of A₁, A₂ in the boxes below. A₁ = -2 1₂ = 2 Hence the soution will be of the form Solve the PDE with the initial conditions u(x, y) = (x +₁y) + (z + √₂y). u (7,0) = 6 sin (r), uy (z,0)=0. Enter the expression for u(z,y) in the box below using Maple syntax. u(x, y) = Note: the expression should be in terms of z and y, but not X₁, X₂-

Suppose that λ =A₁, A₂ are constants such that u(z,y) = F (z+ Ay) statisfied the PDE 82 -4 ( 5²2 U (2, 3)) + 3,²2 u (x, y) = 0 dy2 for any twice-differentiable function of one variable F(s). Suppose also that X₁ <₂, enter the values of A₁, A₂ in the boxes below. A₁ = -2 1₂ = 2 Hence the soution will be of the form Solve the PDE with the initial conditions u(x, y) = (x +₁y) + (z + √₂y). u (7,0) = 6 sin (r), uy (z,0)=0. Enter the expression for u(z,y) in the box below using Maple syntax. u(x, y) = Note: the expression should be in terms of z and y, but not X₁, X₂-

Advanced Engineering Mathematics
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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Suppose that A = A₁, A₂ are constants such that u(x,y) = F(z + Ay) statisfied the PDE -4 (0-2 ² (2,3)) + 2² u (x,y) = 0 u dy2 for any twice-differentiable function of one variable F(s). Suppose also that X₁ ≤₂, enter the values of A₁, A₂ in the boxes below. A₁ = -2 1₂=2 Hence the soution will be of the form Solve the PDE with the initial conditions u(x,y) = (x + ₁ y) + (1 + √₂y). u (1,0) = 6 sin(x), uy (z,0)=0. Enter the expression for u(z,y) in the box below using Maple syntax. U(x, y) = Note: the expression should be in terms of z and y, but not X₁, X₂-
Transcribed Image Text:Suppose that A = A₁, A₂ are constants such that u(x,y) = F(z + Ay) statisfied the PDE -4 (0-2 ² (2,3)) + 2² u (x,y) = 0 u dy2 for any twice-differentiable function of one variable F(s). Suppose also that X₁ ≤₂, enter the values of A₁, A₂ in the boxes below. A₁ = -2 1₂=2 Hence the soution will be of the form Solve the PDE with the initial conditions u(x,y) = (x + ₁ y) + (1 + √₂y). u (1,0) = 6 sin(x), uy (z,0)=0. Enter the expression for u(z,y) in the box below using Maple syntax. U(x, y) = Note: the expression should be in terms of z and y, but not X₁, X₂-
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