Suppose that in solving an equation over the interval [0,360°), you reach the step sin 0= --- 2 Choose the correct answer below. OA. Because -30° is not in the range of the inverse sine function. O B. Because the solution should be in the interval [0,360°). OC. Because sin 0 = - 0= -150°. when 0= - 2 Why is -30° not a correct answer?
Suppose that in solving an equation over the interval [0,360°), you reach the step sin 0= --- 2 Choose the correct answer below. OA. Because -30° is not in the range of the inverse sine function. O B. Because the solution should be in the interval [0,360°). OC. Because sin 0 = - 0= -150°. when 0= - 2 Why is -30° not a correct answer?
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Why is -30° not a correct answer?
Suppose that in solving an equation over the interval [0,360°), you reach the step sin 0= -
2
Choose the correct answer below.
O A. Because -30° is not in the range of the inverse sine function.
O B. Because the solution should be in the interval [0,360°).
OC. Because sin 0 =
-
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when 0-150°.
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Transcribed Image Text:1
Why is -30° not a correct answer?
Suppose that in solving an equation over the interval [0,360°), you reach the step sin 0= -
2
Choose the correct answer below.
O A. Because -30° is not in the range of the inverse sine function.
O B. Because the solution should be in the interval [0,360°).
OC. Because sin 0 =
-
Capstk
80°F
Mostly cloudy
1
7
O
A
1
2
when 0-150°.
@
2
N
W
S
#
3
E
D
H
COLO
CF
R
%
C
5
F
T
G
P
...
7
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