Suppose that, in fact, the total cholesterol level of all men aged 20-34 follows the Normal distribution with mean μ = 182 milligrams per deciliter (mg/dL) and standard deviation o = 37 mg/dL. Use Table A if necessary. Choose an SRS of 100 men from this population. What is the sampling distribution of x? N(182 mg/dL, 0.37 mg/dL) distribution ON(182 mg/dL, 37 mg/dL) distribution N(182 mg/dL, 3.7 mg/dL) distribution N(1.82 mg/dL, 0.37 mg/dL) distribution What is the probability that takes a value between 180 and 184 mg/dL? This is the probability that x estimates μ within + 2 mg/dL. O 0.7054 MacBook Air

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**Text for Educational Website**

Choose an SRS of 100 men from this population.

### Sampling Distribution Question

**What is the sampling distribution of \(\bar{x}\)?**

- \(N(182 \text{ mg/dL}, 0.37 \text{ mg/dL}) \text{ distribution}\)
- \(N(182 \text{ mg/dL}, 37 \text{ mg/dL}) \text{ distribution}\)
- \(N(182 \text{ mg/dL}, 3.7 \text{ mg/dL}) \text{ distribution}\)
- \(N(1.82 \text{ mg/dL}, 0.37 \text{ mg/dL}) \text{ distribution}\)

### Probability Question

**What is the probability that \(\bar{x}\) takes a value between 180 and 184 mg/dL? This is the probability that \(\bar{x}\) estimates \(\mu\) within \(\pm 2 \text{ mg/dL}\).**

- \(0.7054\)
- \(0.4108\)
- \(0.2946\)
- \(0.5400\)

---

No graphs or diagrams are present in the image.
Transcribed Image Text:**Text for Educational Website** Choose an SRS of 100 men from this population. ### Sampling Distribution Question **What is the sampling distribution of \(\bar{x}\)?** - \(N(182 \text{ mg/dL}, 0.37 \text{ mg/dL}) \text{ distribution}\) - \(N(182 \text{ mg/dL}, 37 \text{ mg/dL}) \text{ distribution}\) - \(N(182 \text{ mg/dL}, 3.7 \text{ mg/dL}) \text{ distribution}\) - \(N(1.82 \text{ mg/dL}, 0.37 \text{ mg/dL}) \text{ distribution}\) ### Probability Question **What is the probability that \(\bar{x}\) takes a value between 180 and 184 mg/dL? This is the probability that \(\bar{x}\) estimates \(\mu\) within \(\pm 2 \text{ mg/dL}\).** - \(0.7054\) - \(0.4108\) - \(0.2946\) - \(0.5400\) --- No graphs or diagrams are present in the image.
### Understanding Cholesterol Levels in Adults: A Normal Distribution Analysis

Suppose that the total cholesterol level of all men aged 20-34 follows a Normal distribution with mean \( \mu = 182 \) milligrams per deciliter (mg/dL) and standard deviation \( \sigma = 37 \) mg/dL.

**Instructions:**
Use Table A if necessary.

---

**Exercise:**

Choose an SRS (Simple Random Sample) of 100 men from this population.

**Question 1:**

What is the sampling distribution of \( \bar{x} \)?

- \( \circ \ N(182 \text{ mg/dL}, 0.37 \text{ mg/dL}) \) distribution
- \( \circ \ N(182 \text{ mg/dL}, 37 \text{ mg/dL}) \) distribution
- \( \circ \ N(182 \text{ mg/dL}, 3.7 \text{ mg/dL}) \) distribution
- \( \circ \ N(1.82 \text{ mg/dL}, 0.37 \text{ mg/dL}) \) distribution

**Question 2:**

What is the probability that \( \bar{x} \) takes a value between 180 and 184 mg/dL? This is the probability that \( \bar{x} \) estimates \( \mu \) within \( \pm 2 \text{ mg/dL} \).

- \( \circ \ 0.7054 \)

---

This educational exercise helps students understand concepts related to sampling distributions and probability estimation using real-world data.
Transcribed Image Text:### Understanding Cholesterol Levels in Adults: A Normal Distribution Analysis Suppose that the total cholesterol level of all men aged 20-34 follows a Normal distribution with mean \( \mu = 182 \) milligrams per deciliter (mg/dL) and standard deviation \( \sigma = 37 \) mg/dL. **Instructions:** Use Table A if necessary. --- **Exercise:** Choose an SRS (Simple Random Sample) of 100 men from this population. **Question 1:** What is the sampling distribution of \( \bar{x} \)? - \( \circ \ N(182 \text{ mg/dL}, 0.37 \text{ mg/dL}) \) distribution - \( \circ \ N(182 \text{ mg/dL}, 37 \text{ mg/dL}) \) distribution - \( \circ \ N(182 \text{ mg/dL}, 3.7 \text{ mg/dL}) \) distribution - \( \circ \ N(1.82 \text{ mg/dL}, 0.37 \text{ mg/dL}) \) distribution **Question 2:** What is the probability that \( \bar{x} \) takes a value between 180 and 184 mg/dL? This is the probability that \( \bar{x} \) estimates \( \mu \) within \( \pm 2 \text{ mg/dL} \). - \( \circ \ 0.7054 \) --- This educational exercise helps students understand concepts related to sampling distributions and probability estimation using real-world data.
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