Suppose that in a certain town with a population of 5000 households, 3000 of the households have cell phones, 2000 have computers at home, and 1500 have both cell phones and computers. A household in the town is selected at random. Let P be the event that the household has a cell phone and C be the event that the household has a computer. If the household owns a cell phone, what is the probability that it does not own a computer? O P (C | P') = 1 O P(P|C") = } O P(C | P) = |3D O P(C' | P) = ;
Suppose that in a certain town with a population of 5000 households, 3000 of the households have cell phones, 2000 have computers at home, and 1500 have both cell phones and computers. A household in the town is selected at random. Let P be the event that the household has a cell phone and C be the event that the household has a computer. If the household owns a cell phone, what is the probability that it does not own a computer? O P (C | P') = 1 O P(P|C") = } O P(C | P) = |3D O P(C' | P) = ;
A First Course in Probability (10th Edition)
10th Edition
ISBN:9780134753119
Author:Sheldon Ross
Publisher:Sheldon Ross
Chapter1: Combinatorial Analysis
Section: Chapter Questions
Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...
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Transcribed Image Text:Suppose that in a certain town with a population of 5000 households,
3000 of the households have cell phones,
2000 have computers at home, and
1500 have both cell phones and computers.
A household in the town is selected at random.
Let P be the event that the household has a cell phone and C be the event that the household
has a computer.
If the household owns a cell phone, what is the probability that it does not own a computer?
O P(C | P') = }
2
O P(P|C')=
O P(C | P)' = =
O P(C' | P) =
1
2
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