Suppose that f(x, y) : = Y 1 + x at which {(x, y) | 0 ≤ x ≤ 1, - x≤ y ≤ √x}. a Then the double integral of f(x, y) over D is = [ f(x, y)dady Round your answer to four decimal places.

Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
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5.2.4

**Mathematical Problem: Evaluating a Double Integral**

Let \( f(x, y) = \frac{y}{1+x} \) over the region \( D \), where:

\[ D = \{ (x, y) \mid 0 \leq x \leq 1, -x \leq y \leq \sqrt{x} \} \]

The graph depicts the region \( D \) on the Cartesian plane:

- It is bounded on the left by the vertical line at \( x = 0 \).
- The right boundary is the vertical line at \( x = 1 \).
- The lower boundary is the line \( y = -x \).
- The upper boundary is the curve \( y = \sqrt{x} \).

The region \( D \) appears as a triangular area with a curved hypotenuse, forming a combination of linear and parabolic boundaries.

**Objective:**

Calculate the double integral of \( f(x, y) \) over the region \( D \):

\[
\iint_D f(x, y) \, dx \, dy = \text{(Result rounded to four decimal places)}
\]
Transcribed Image Text:**Mathematical Problem: Evaluating a Double Integral** Let \( f(x, y) = \frac{y}{1+x} \) over the region \( D \), where: \[ D = \{ (x, y) \mid 0 \leq x \leq 1, -x \leq y \leq \sqrt{x} \} \] The graph depicts the region \( D \) on the Cartesian plane: - It is bounded on the left by the vertical line at \( x = 0 \). - The right boundary is the vertical line at \( x = 1 \). - The lower boundary is the line \( y = -x \). - The upper boundary is the curve \( y = \sqrt{x} \). The region \( D \) appears as a triangular area with a curved hypotenuse, forming a combination of linear and parabolic boundaries. **Objective:** Calculate the double integral of \( f(x, y) \) over the region \( D \): \[ \iint_D f(x, y) \, dx \, dy = \text{(Result rounded to four decimal places)} \]
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