Suppose that f(x) is an invertible function (that is, has an inverse function), and that the slope of the tangent line to the curve y = f(x) at the point (2, -4) is -0.2. Then: The slope of the tangent line to the curve y = f-¹(x) at the point (-4, 2) is -0.2. The slope of the tangent line to the curve y = f-1(x) at the point (2, -4) is -5. The slope of the tangent line to the curve y = f-1(x) at the point (2, -4) is 5. The slope of the tangent line to the curve y = f-1(x) at the point (-4, 2) is -5. The slope of the tangent line to the curve y = f-1(x) at the point (-4, 2) is 5.

College Algebra
10th Edition
ISBN:9781337282291
Author:Ron Larson
Publisher:Ron Larson
Chapter2: Functions And Their Graphs
Section2.3: Analyzing Graphs Of Functions
Problem 6ECP
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Suppose that f(x) is an invertible function (that is, has an inverse function), and that
the slope of the tangent line to the curve y = f(x) at the point (2, -4) is -0.2. Then:
The slope of the tangent line to the curve y = f-¹(x) at the point (-4, 2) is -0.2.
The slope of the tangent line to the curve y = f-¹(x) at the point (2,-4) is -5.
The slope of the tangent line to the curve y = f-¹(x) at the point (2, -4) is 5.
The slope of the tangent line to the curve y = f-1(x) at the point (-4, 2) is -5.
The slope of the tangent line to the curve y = f-1(x) at the point (-4, 2) is 5.
Transcribed Image Text:Suppose that f(x) is an invertible function (that is, has an inverse function), and that the slope of the tangent line to the curve y = f(x) at the point (2, -4) is -0.2. Then: The slope of the tangent line to the curve y = f-¹(x) at the point (-4, 2) is -0.2. The slope of the tangent line to the curve y = f-¹(x) at the point (2,-4) is -5. The slope of the tangent line to the curve y = f-¹(x) at the point (2, -4) is 5. The slope of the tangent line to the curve y = f-1(x) at the point (-4, 2) is -5. The slope of the tangent line to the curve y = f-1(x) at the point (-4, 2) is 5.
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