Suppose that [ f(a)da = 7, and b) ²9(2 g(x) dx = 29, compute the following integrals: 5 S* 158 (2) - [5f(x) - 4g(x)]dx = f(x) dx = -7, and 5 [*[3ƒ(z) + 2g(a)]dx = g(x) dx = 13, and

Calculus: Early Transcendentals
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Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
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Suppose that 

\[
\int_0^5 f(x) \, dx = 7, \quad \text{and} \quad \int_0^2 f(x) \, dx = -7, \quad \text{and} \quad \int_0^5 g(x) \, dx = 13, \quad \text{and} \quad \int_0^2 g(x) \, dx = 29,
\]

compute the following integrals:

a) \(\int_0^5 [5f(x) - 4g(x)] \, dx = \) \([ \hspace{2cm} ]\)

b) \(\int_2^5 [3f(x) + 2g(x)] \, dx = \) \([ \hspace{2cm} ]\)
Transcribed Image Text:Suppose that \[ \int_0^5 f(x) \, dx = 7, \quad \text{and} \quad \int_0^2 f(x) \, dx = -7, \quad \text{and} \quad \int_0^5 g(x) \, dx = 13, \quad \text{and} \quad \int_0^2 g(x) \, dx = 29, \] compute the following integrals: a) \(\int_0^5 [5f(x) - 4g(x)] \, dx = \) \([ \hspace{2cm} ]\) b) \(\int_2^5 [3f(x) + 2g(x)] \, dx = \) \([ \hspace{2cm} ]\)
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