Suppose that f(2) = -4, g(2) = 5, f '(2) = -1, and g'(2) = 2. Find h'(2). (a) h(x) = 3f(x) – 5g(x) h'(2) = |-13 h(x) = f(x)g(x) h'(2) : (b) = |-23 f(x) g(x) = 3/25 (c) h(x) h'(2) g(x) 1 + f(x) (d) h(x) h'(2) = -1/9

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