Suppose that f is a function given as ƒ(x) = = Simplify the expression f(x + h). f(x + h) = Simplify the difference quotient, f(x+h)-f(x) h = f'(x) = lim h→0 1 2x - 5 ƒ(x + h) − f(x) h The derivative of the function at x is the limit of the difference quotient as h approaches zero. f(x +h)-f(x) h =
Suppose that f is a function given as ƒ(x) = = Simplify the expression f(x + h). f(x + h) = Simplify the difference quotient, f(x+h)-f(x) h = f'(x) = lim h→0 1 2x - 5 ƒ(x + h) − f(x) h The derivative of the function at x is the limit of the difference quotient as h approaches zero. f(x +h)-f(x) h =
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Question
![Suppose that f is a function given as f(x)
Simplify the expression f(x + h).
f(x + h) =
=
Simplify the difference quotient,
f(x +h)-f(x)
h
=
=
1
2x - 5
ƒ(x + h) − f(x)
-
h
=
The derivative of the function at x is the limit of the difference quotient as h approaches zero.
ƒ'(x) = lim
f(x + h) − f(x)
h→0
h](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Ffdc4bd04-a070-4f0a-8c81-81114a590c8c%2Fa707aa44-ff31-4ab0-bff2-191f3f221445%2Fnnla2kt_processed.png&w=3840&q=75)
Transcribed Image Text:Suppose that f is a function given as f(x)
Simplify the expression f(x + h).
f(x + h) =
=
Simplify the difference quotient,
f(x +h)-f(x)
h
=
=
1
2x - 5
ƒ(x + h) − f(x)
-
h
=
The derivative of the function at x is the limit of the difference quotient as h approaches zero.
ƒ'(x) = lim
f(x + h) − f(x)
h→0
h
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