Suppose that an urn contains (8 red balls and 4 white) balls. We draw 2 balls fre the urn without replacement. If we assume that at each draw each ball in the urn equally likely to be chosen, what is the probability that both balls drawn are red
Suppose that an urn contains (8 red balls and 4 white) balls. We draw 2 balls fre the urn without replacement. If we assume that at each draw each ball in the urn equally likely to be chosen, what is the probability that both balls drawn are red
A First Course in Probability (10th Edition)
10th Edition
ISBN:9780134753119
Author:Sheldon Ross
Publisher:Sheldon Ross
Chapter1: Combinatorial Analysis
Section: Chapter Questions
Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...
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Transcribed Image Text:**Transcription:**
Suppose that an urn contains 8 red balls and 4 white balls. We draw 2 balls from the urn without replacement. If we assume that at each draw each ball in the urn is equally likely to be chosen, what is the probability that both balls drawn are red?
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**Explanation:**
This text presents a probability problem involving drawing balls from an urn. The urn contains a total of 12 balls: 8 red and 4 white. The task is to calculate the probability of drawing 2 red balls in succession without replacing any balls back into the urn.
Key concepts to consider when solving this problem include:
1. **Without Replacement**: This means once a ball is drawn, it is not returned, affecting the total number and proportion of balls for the subsequent draw.
2. **Probability Calculation**: The scenario requires calculating the probability for two sequential draws, which involves conditional probability.
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