Suppose that A was generated uniformly at random from all 8 byte strings. What is the probability that the second binary digit of A is 1? A) 1 B) 1/2 C) 1/3 D) 1/5
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- Implement the following error detection and error correction algorithms using C programming for Hamming code. For Hamming codes, flip a bit in the data and implement the algorithm to correct the same on the receiver side.Let a “binary code” be the set of all binary words, each consisting of 6 bits (i.e., 0 or 1 digits). For example, 001101 is a word in this code.In a given 32-bit floating-point representation of numbers, if the number of bits of the mantissa is reduced to accommodate an increase in the number of bits of the exponent, this will result in the following: (select the best answer) Increased range of the numbers at the expense of the precision Increased precision of the numbers at the expense of the range Both range and precision increase Both range and precision decrease
- Q6/Full the following blanks (1101 1010)BCD(5211) = ( )BCD(3321)=( )EX-3=( )16 (1101 1010)BCD(5211) = (1110 0111)BCD(3321)=(1011001)EX-3= (56)16 O None of them (1101 1010)BCD(5211) = (1101 O 0111)BCD(3321)=(1011001)EX-3= (2B)16 (1101 1010)BCD(5211) = (1011 O 1110) BCD (3321)=(1000111)EX-3= (44)16 (1101 1010)BCD(5211) = (1110 O 1100) BCD (3321)=(1010110)EX-3= (A6)16Consider a 16-bit binary floating point number representation system: + | SE E E E E E m m т m m m m m m The first bit of the exponent is dedicated to its sign. Assume that the mantissa must start with a '1'. Use this system to answer the following question What is the smallest (magnitude) number that can be represented with this system?Encode (800) 555-0012 in ASCII, including punctuation. 5.Translate the following hexadecimal into binary and then into ASCII: 68 65 78 61 64 65 63 69 6D 61 6C You have discovered the following string of binary ASCII code; figure out what they mean: 01010111 01100001 01111001 00100000 01110100 01101111 00100000 01100111 01101111 00100001
- Q1/ B. Apply Addition and Multiplication: * i. (101)2 with (011)2 ii. (7)10 with (2)10 iii. (1000), with (011)2 iv. (12)10 with (15)10True or false: A dataword (k) and a codeword (n) vary in that the k=n+FCS (Frame Check Sequence).6-In the representation Complement to 1, we the number when Code the absolute value thus is negative: A = True B- False 7- The result in base 10' A - 44.25 B-42015 C- 51. 13 45. 75 8- The result AT 40. B + 61 q of the transformation (101001.10) 2 usi o the transformation (52) a in bose 10 is: C² 42 D-41 WWW 30 O