Suppose that a random variable Z has a standard normal distribution. Find a such that P(Z > a) = 0.229. Give your answer to two decimal places. You may find this Z-table useful. a = -2.00 Incorrect
Suppose that a random variable Z has a standard normal distribution. Find a such that P(Z > a) = 0.229. Give your answer to two decimal places. You may find this Z-table useful. a = -2.00 Incorrect
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![Title: Solving for a Z-Value in a Standard Normal Distribution
**Problem Statement:**
Suppose that a random variable \( Z \) has a standard normal distribution. Find \( a \) such that \( P(Z > a) = 0.229 \). Give your answer to two decimal places. You may find this Z-table useful.
**Input Box:**
\( a = \) [Input Field]
(Current Answer: \(-2.00\), marked as Incorrect)
---
To solve this problem, you need to use the Z-table to find the value of \( a \) that corresponds to a right-tail probability of 0.229 in a standard normal distribution. The Z-table provides the cumulative probabilities for different Z-scores, which can help identify the correct value for \( a \).
Steps to solve:
1. Look up the cumulative probability on the Z-table that equals \( 1 - 0.229 = 0.771 \).
2. Find the corresponding Z-score for this cumulative probability.
3. Input the correct Z-score rounded to two decimal places.
This exercise helps in understanding the application of the standard normal distribution in calculating probabilities and finding specific percentiles.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F034292c9-9285-4cd3-9ca8-fd2ff4b549e6%2F6dbb3c97-5c65-48be-86c0-a5e0fe4cb345%2Fzn89gsk_processed.png&w=3840&q=75)
Transcribed Image Text:Title: Solving for a Z-Value in a Standard Normal Distribution
**Problem Statement:**
Suppose that a random variable \( Z \) has a standard normal distribution. Find \( a \) such that \( P(Z > a) = 0.229 \). Give your answer to two decimal places. You may find this Z-table useful.
**Input Box:**
\( a = \) [Input Field]
(Current Answer: \(-2.00\), marked as Incorrect)
---
To solve this problem, you need to use the Z-table to find the value of \( a \) that corresponds to a right-tail probability of 0.229 in a standard normal distribution. The Z-table provides the cumulative probabilities for different Z-scores, which can help identify the correct value for \( a \).
Steps to solve:
1. Look up the cumulative probability on the Z-table that equals \( 1 - 0.229 = 0.771 \).
2. Find the corresponding Z-score for this cumulative probability.
3. Input the correct Z-score rounded to two decimal places.
This exercise helps in understanding the application of the standard normal distribution in calculating probabilities and finding specific percentiles.
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