Suppose that a random variable X has a hypergeometric distribution with parameters n = 36, N = 50, and M = 28. What is the mean of X? Do not round!

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Suppose that a random variable X has a hypergeometric distribution with parameters n = 36, N = 50, and M = 28.

What is the mean of X?

Do not round!

**Understanding Hypergeometric Distributions**

In this example, we are tasked with finding the mean of a random variable \( X \) that follows a hypergeometric distribution. The parameters for this distribution are:

- \( n = 36 \) (the number of draws),
- \( N = 50 \) (the population size),
- \( M = 28 \) (the number of success states in the population).

**Question: What is the mean of \( X \)?**

*Important Note:* 
- Do not round your answer.

For educational purposes, remember that the mean of a hypergeometric distribution is calculated using the formula:

\[ \text{Mean} = n \cdot \frac{M}{N} \]

To find the mean, substitute the given values into the formula.
Transcribed Image Text:**Understanding Hypergeometric Distributions** In this example, we are tasked with finding the mean of a random variable \( X \) that follows a hypergeometric distribution. The parameters for this distribution are: - \( n = 36 \) (the number of draws), - \( N = 50 \) (the population size), - \( M = 28 \) (the number of success states in the population). **Question: What is the mean of \( X \)?** *Important Note:* - Do not round your answer. For educational purposes, remember that the mean of a hypergeometric distribution is calculated using the formula: \[ \text{Mean} = n \cdot \frac{M}{N} \] To find the mean, substitute the given values into the formula.
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