Suppose that a random sample of ten recently sold houses in a certain city has a mean sales price of $285,000, with a standard deviation of $5000. Unde assumption that house prices are normally distributed, find a 95% confidence interval for the mean sales price of all houses in this community. Then find lower limit and upper limit of the 95% confidence interval. Carry your intermediate computations to at least three decimal places. Round your answers to the nearest whole number. (If necessary, consult a list of formulas.) Lower limit: $|| Upper limit: S

Q: suppose that 50 students were randomly sampled and their mean age was 30.4 years old. the population…

A:

Q: Suppose that a random sample of 9 adult U.S. males has a mean height of 69 inches with a standard…

A:

Q: If n=32, ¯xx¯(x-bar)=31, and s=14, construct a confidence interval at a 95% confidence level. Assume…

A: Given: x¯=31n=32s=1495% confidence level

Q: Out of a sample of 600 adults aged 18 to 30, 162 still lived with their parents. Based on this,…

A:

Q: If n- 22, - 44, and s 12, construct a confidence interval at a 95% confidence level. Assume the data…

A: Solution We solve it by using excel

Q: If n=30, ¯xx¯(x-bar)=43, and s=16, construct a confidence interval at a 98% confidence level. Assume…

A:

Q: If n = 10, ¯xx¯ = 43, and s = 8, construct a confidence interval at a 90% confidence level. Assume…

A: Since population standard deviation is unknown, Use t-distribution to find t-critical value. Find…

Q: If n = 15, 43, and s = 9, construct a confidence interval at a 98 % confidence level. Assume the…

A:

Q: If n = 280 and ô (p-hat) = 0.8, construct a 90% confidence interval. Give your answers to three…

A: given data sample size (n) = 280p^ = 0.890% ci p.

Q: The mean scores of a random sample of 17 students who took a special test is 83.5. If the standard…

A: Given;sample size(n)=17sample mean(x¯)=83.5sample s.d.(s)=4.1for confidence level 95%, significance…

Q: If n=22, ¯xx¯(x-bar)=45, and s=4, construct a confidence interval at a 90% confidence level. Assume…

A: Ans -   Given the level of confidence interval   90 %                      Then   α = 1 - 0.90 =…

Q: If n=10, ī(x-bar)=37, and s=19, construct a confidence interval at a 95% confidence level. Assume…

A: From the provided information, Sample size (n) = 10 Sample mean (x̄) = 37 Standard deviation (s) =…

Q: Solve the following. Show your complete solution. Fifty randomly selected jeepneys were stopped, and…

A:

Q: If n=15, ¯xx¯(x-bar)=30, and s=2, construct a confidence interval at a 98% confidence level. Assume…

A: Given Sample size n = 15  degree of freedom = n-1 =14 x the level of confidence interval   98 %…

Q: If n = 22, ¯xx¯ = 36, and s = 14, construct a confidence interval at a 98% confidence level. Assume…

A: From the provided information, Sample size (n) = 22 Sample mean (x̄) = 36 Standard deviation (s) =…

Q: Suppose that the a college wants to have an idea of the average SAT score of the incoming freshman…

A: The confidence level is 0.90, the standard deviation is 310 and margin of error E is 50.

Q: If n=12, (x-bar)=33, and s=16, construct a confidence interval at a 80% confidence level. Assume the…

A:

Q: If n=22, ¯xx¯(x-bar)=46, and s=8, construct a confidence interval at a 98% confidence level. Assume…

A: It is given that mean and standard deviation are 46 and 8, respectively.

Q: According to a report on consumer fraud and identity theft, Indiana had 1671 complaints of identity…

A:

Q: If n-19, ž(x-bar)-43, and s-8, construct a confidence interval at a 90% confidence level. Assume the…

A: Given: n = 19, x¯ = 43, s = 8 Confidence level = 90%

Q: If n = 15, ¯x = 50, and s = 9, construct a confidence interval at a 90% confidence level. Assume the…

A:

Q: If n=17, (x-bar)-45, and o =12, construct a confidence interval at a 80% confidence level. Assume…

A: Given X-bar=45 S=12 n=17

Q: We wish to estimate what percent of adult residents in a certain county are parents. Out of 500…

A: Given X=25 n=500 95% confidence interval

Q: In a random sample of 500 Americans, 25% indicated that they have a cat for a pet. Estimate with 97%…

A:

Q: In a random sample of 500 Americans, 50% indicated that they have a cat for a pet. Estimate with 95%…

A: Given information

Q: A study of the consultants in a particular industry has determined that the standard deviation of…

A: Solution-: Given: x¯=113,n=50,σ=18,c=0.95 We want to find the lower limit and upper limit of the 95%…

Q: If n=13, ¯x(x-bar)=44, and s=3, construct a confidence interval at a 99% confidence level. Assume…

A: Here, n is 13, x-bar is 44, and s is 3. Critical value: Using Excel formula…

Q: lculating the confidence interval.

A: x Freq 1 3 2 5 3 19 4 7 5 6 Total 40

Q: 13, ¤(x-bar)=39, and s=16, construct a confidence interval at a 90% confidence level. Assume the…

A: From the given information, n=13 x-bar=39 s=16 Confidence level=90% Significance level=10%…

Q: Free of CVD       Prevalent CVD    Total Men          1548                 244                 1792…

A: Given The tota number of men with CVD =244The tota number of women with CVD =135The tota number of…

Q: If n=15, ¯xx¯(x-bar)=40, and s=9, construct a confidence interval at a 98% confidence level. Assume…

A:

Q: We wish to estimate what percent of adult residents in a certain county are parents. Out of 100…

A: According to the given information, we have Out of 100 adult residents sampled, 88 had kids. 99%…

Q: Out of 800 adults selected randomly from one town, 272 have health insurance. Find a 90% confidence…

A: Given,   The sample proportion is,

Q: We wish to estimate what percent of adult residents in a certain county are parents. Out of 600…

A: Solution

Q: If n=15, ¯xx¯(x-bar)=33, and s=19, construct a confidence interval at a 80% confidence level. Assume…

A: Given' :  sample mean xbar=33  sample size n=15  sample standard deviations s=14  then to find 80%…

Q: If n = 15, ¯xx¯ = 43, and s = 11, construct a confidence interval at a 98% confidence level. Assume…

A: Given that, The degree of freedom is, Critical values: The t-critical values for a two-tailed…

Q: study of the consultants in a particular industry has determined that the standard deviation of the…

A:

Q: Create a 95% confidence interval for the percent of people who shop on Amazon, using the Plus 4…

A: Given: ∝ = 0.05 n = 50 x = 47 Thus, p^= x/n = 47/50 = 0.94

Q: f n=19, sample mean=50, and s =8, construct a confidence interval at a 99% confidence level. Assume…

A:

Q: If n = 530 and X = 424, construct a 99% confidence interval for the population proportion, p. Give…

A:

Q: a sample of 25 automobiles shows that the mean price was $20,500 with standard deviation of $2,500.…

A: Givensample size = n = 25Mean price = $20,500Standard deviation = $2500 The distribution is normal.…

Q: If n = 100 and p̂ (p-hat) = 0.4, construct a 95% confidence interval.

A: To find the 95% confidence interval for the population proportion. Given that,…

Q: Solve the following. Show your complete solution The incoming freshman students of a particular…

A: Given that   We have to 90% confidence interval for the mean difference of the exam scores :

Q: If n=13, ¯xx¯(x-bar)=37, and s=9, construct a confidence interval at a 80% confidence level. Assume…

A: Givenn =13x = 37s=9confidence interval =80%

Q: Suppose we wish to construct a 95% confidence interval for the population proportion of fans in…

A: Given that, Total fans = 200 130 answered yes 95% confidence level