Suppose that a new treatment is successful in curing a common ailment 72% of the time. If the treatment is tried on a random sample of 120 patients,approximate the probability that fewer than 89 will be cured. Use the normal approximation to the binomial with a correction for continuity.Round your answer to at least three decimal places. Do not round any intermediate steps.(If necessary, consult a list of formulas.)ExplanationCheckXSⒸ2022 McGraw Hill LLC. All Rights Reserved. Terms of UsePrivacy Center 1 Ac

Given,n=120p=0.72q=1-0.72=0.28np=120×0.72=86.4≥5nq=120×0.28=33.6≥5we can use nomal…

Answered: Suppose that a new treatment is…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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For each part below, if a regression has the given coefficient of correlation, find its coefficient of determination. Your answer should be accurate to at least four decimal places. a) Coefficient of correlation is -0.72. Coefficient of determination is 0 b) Coefficient of correlation is 0.84. Coefficient of determination is 0
Previously, De Anza's statistics students estimated that the amount of change daytime statistics students carry is exponentially distributed with a mean of $0.88. Suppose that we randomly pick 25 daytime statistics students. Find the probability that an individual had between $0.80 and $1.00. Graph the situation, and shade in the area to be determined.
Ocean currents are important in studies of climate change, as well as ecology studies of dispersal of plankton. Drift bottles are used to study ocean currents in the Pacific near Hawaii, the Solomon Islands, New Guinea, and other islands. Let x represent the number of days to recovery of a drift bottle after release and y represent The distance from point of release to point of recovery in km/100. The following data a representative of one study using drift bottles to study ocean currents. x day 72 79 32 96 203 y km/100 14.8 19.6 5.3 11.8 35.1 Σx=482 Σy=86.6 Σx2=62874 Σy2=2002.54 Σxy=11041.7 r=.93787 use a 1% level of significance to test the claim p>0.(use 2 decimal places) t=critical t= Se=4.4913 a=1.4966 b=.1641 D) find the predicted distance (km/100) when a drift bottle has been floating for 80 days.(use 2 decimal places) find a 90% confidence interval for your prediction of part D. (use 2 decimal places) lower limit=___km/100upper limit=___km/100 he was a 1% level of…
Interpret the regression results.
Please do not use Excel to find the answers
Please show/explain method if using excel
Find an example of regression that lead to an important discovery. Be sure to give proper attribution or credit to the source. Discuss how and why it lead to a discovery in at least 6 sentences.
You estimated a regression with the following output. Source | SS df MS Number of obs = 423 -------------+---------------------------------- F(1, 421) = 267.80 Model | 8758968.84 1 8758968.84 Prob > F = 0.0000 Residual | 13769523.8 421 32706.7074 R-squared = 0.3888 -------------+---------------------------------- Adj R-squared = 0.3873 Total | 22528492.7 422 53385.0537 Root MSE = 180.85 ------------------------------------------------------------------------------ Y | Coef. Std. Err. t P>|t| [95% Conf. Interval] -------------+---------------------------------------------------------------- X | 6.150402 .3758334 16.36 0.000 5.411658 6.889145 _cons | -8.022201 24.02003 -0.33 0.739 -55.23632 39.19192…
The data show the bug chirps per minute at different temperatures. Find the regression equation, letting the first variable be the independent (x) variable. Find the best predicted temperature for a time when a bug is chirping at the rate of 3000 chirps per minute. Use a significance level of 0.05. What is wrong with this predicted value? Chirps in 1 min 1118 796 1161 918 1103 1219 Temperature (F) 82 72.2 92.2 73 87.5 94.4
Find the z-score corresponding to the given value and use the z-score to determine whether the value is significantly low or high. Consider a score to be significantly low if its z-score is less than or equal to -2. Consider a z-score to be significantly high if it is greater than or equal to 2. Round the z-score to the nearest tenth if necessary. A body temperature of 96.7° F given that human body temperatures have a mean of 98.20° F and a standard deviation of 0.62°.

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