Suppose that a day's production of 800 manufactured parts contains 50 parts that do not conform to customer requirements. Two parts are selected at random in succession and without replacement, from the batch. Let the random variable X equal the number of nonconforming parts in the sample. Then the cumulative distribution function of X is: F(0) = 0.778, F(1) = 0.986, F(2) = 1 %3D %3D %3D F(0) = 0.846, F(1) = 0.993, F(2) = 1 %3D F(0) = 0.879, F(1) = 0.996, F(2) = 1 O F(0) = 0.577, F(1) = 0.736, F(2) = 1 %3D %3D
Suppose that a day's production of 800 manufactured parts contains 50 parts that do not conform to customer requirements. Two parts are selected at random in succession and without replacement, from the batch. Let the random variable X equal the number of nonconforming parts in the sample. Then the cumulative distribution function of X is: F(0) = 0.778, F(1) = 0.986, F(2) = 1 %3D %3D %3D F(0) = 0.846, F(1) = 0.993, F(2) = 1 %3D F(0) = 0.879, F(1) = 0.996, F(2) = 1 O F(0) = 0.577, F(1) = 0.736, F(2) = 1 %3D %3D
A First Course in Probability (10th Edition)
10th Edition
ISBN:9780134753119
Author:Sheldon Ross
Publisher:Sheldon Ross
Chapter1: Combinatorial Analysis
Section: Chapter Questions
Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...
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Transcribed Image Text:Suppose that a day's production of 800 manufactured parts contains 50 parts that do
not conform to customer requirements. Two parts are selected at random in succession
and without replacement, from the batch. Let the random variable X equal the number
of nonconforming parts in the sample. Then the cumulative distribution function of X is:
F(0) = 0.778, F(1) = 0.986, F(2) = 1
%3D
%3D
%3D
F(0) = 0.846, F(1) = 0.993, F(2) = 1
%3D
F(0) = 0.879, F(1) = 0.996, F(2) = 1
O F(0) = 0.577, F(1) = 0.736, F(2) = 1
%3D
%3D
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