Suppose that a customer is purchasing a car. He conducts anexperiment in which he puts 10 gallons of gas in the car anddrives it until it runs out of gas. He conducts this experiment 15times on each car and records the number of miles driven.Range for Car 2R= 70 mi / 10 gal(Type an integer or decimal rounded to one decimalplace as needed.)Full data setSample standard deviation for Car 1s= mi / 10 gal(Type an integer or decimal rounded to one decimalplace as needed.)Car 1245242215244220265291160284251169319257306267Sample standard deviation for Car 2Car 2s= mi / 10 gal(Type an integer or decimal rounded to one decimalplace as needed.)230206214236242256245255241264276252250251257

Answered: Suppose that a customer is purchasing a…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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The blood pressure in millimeters was measured for a large sample of people. The average pressure is 140 mm, and the SD of the measurements is 20 mm. The histogram looks reasonably like a normal curv Use the normal curve to estimate the following percentages. Choose the answer that is closest to being correct. A 19.1% B 30.9% C 38.2% D 69.1% E 68.27% A The percentage of people with blood pressure between 130 and 150 mm. B The percentage of people with blood pressure between 140 and 150 mm. D The percentage of people with blood pressure over 150 mm.
Aleks spins a 9 sided spinner 56 times. Each of the nine sides has a different colour on it. He records the number of times that he spins the colour purple. What values need to be determined in order to use a normal approximation? Determine these values.
age 2 of 6 b. should not be rejected. c. should be revised. 70°F Sunny d. should not be tested. ANSWER: b MSC 600 Quantitative Methods 7. Part of an ANOVA table is shown below. Source of Variation Between Treatments Within Treatments (Error) TOTAL 480 18 The mean square due to treatments (MSTR) is a. 20. b. 60. c. 18 d. 15. ANSWER: b 8. Part of an ANOVA table is shown below. Source of Sum of Variation "Squares Between Treatments 180 Within Treatments (Error) TOTAL 1105 words Sum of Degrees of SquaresFreedom 180 3 480 The mean square due to error (MSE) is a. 60. b. 15. c. 18. d. 20 ANSWER: 4 W Text Predictions: On Degrees of Freedom 3 18 Mean Square Mean Square Focus 32 F F 00 O Search LAH COLLEGE OF BUSINESS J 7 10 Re SAMSU
Exam scores have a normal distribution with u= 70 and o= 10. Bob's exam score is 80. What is Bob's z-score?
Because the mean is very sensitive to extreme values, it is not a resistant measure of center. By deleting some low values and high values, the trimmed mean is more resistant. To find the 10% trimmed mean for a data set, first arrange the data in order, then delete the bottom 10% of the values and delete the top 10% of the values, then calculate the mean of the remaining values. Use axial loads (pounds) of aluminum cans listed below for cans that are 0.0111 in. thick. Identify any outliers, then compare the median, mean, 10% trimmed mean, and 20% trimmed mean. 247 261 269 273 275 280 282 282 284 285 285 287 290 292 293 296 296 299 311 507 Identify any outliers. Select the correct choice below and, if necessary, fill in the answer box to complete your choice. OA. The outlier(s) is/are pounds. (Type a whole number. Use a comma to separate answers as needed.) C OB. There are no outliers.
"Durable press" cotton fabrics are treated to improve their recovery from wrinkles after washing. "Wrinkle recovery angle" measures how well a fabric recovers from wrinkles. Higher is better. Here are data on the wrinkle recovery angle (in degrees) for two types of treated fabrics: Permafresh Hylite 15 17 12 14 13 16 16 15 14 18 A manufacturer wants to know how large is the difference in mean wrinkle recovery angle. Give a 98% confidence interval for the difference in mean wrinkle recovery angle: [three decimal accuracy] [three decimal accuracy]
Draw the normal curve using the data given b. x = 83. s = 6 a.x = 30. s = 8 %3D
sketch a standard normal curve and shade the area of interest for each problem: 1. Find the area under the standard normal curve that lies to the right of -1.07 0.6 0 4.2

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