Suppose that a certain college class contains 35 students. Of these, 20 are juniors, 19 are physics majors, and 10 are neither. A student is selected at random from the class. (a) What is the probability that the student is both a junior and a physics major? (b) Given that the student selected is a physics major, what is the probability that she is also a junior?

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Intersection and conditional probability
Suppose that a certain college class contains 35 students. Of these, 20 are
juniors, 19 are physics majors, and 10 are neither. A student is selected at
random from the class.
(a) What is the probability that the student is both a junior and a
physics major?
(b) Given that the student selected is a physics major, what is the
probability that she is also a junior?
Write your responses as fractions. (If necessary, consult a list of formulas.)
Aa
Explanation
Check
20ZIMCUraw HlLEGcation. All Rights Resen/ed.
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Transcribed Image Text:Home | iCampus Bb Week 6 – MAT30045... A ALEKS - Shasia Gibb... [c) Careers in Cannabis O PROBABILITY Shasia v Intersection and conditional probability Suppose that a certain college class contains 35 students. Of these, 20 are juniors, 19 are physics majors, and 10 are neither. A student is selected at random from the class. (a) What is the probability that the student is both a junior and a physics major? (b) Given that the student selected is a physics major, what is the probability that she is also a junior? Write your responses as fractions. (If necessary, consult a list of formulas.) Aa Explanation Check 20ZIMCUraw HlLEGcation. All Rights Resen/ed. Terms of Use I Privacy Accessibility II
Expert Solution
Step 1

Given information

Total students = 35

No of junior students = 20

No of physics major = 19

Neither = 10

Either juniors or physics student is = 35 - 10 = 25

N (Juniors U Physics) = 25

N (juniors ∩ physics) = 20 + 19 – 25 = 14

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