Suppose that 6 out of 10 dentists recommend MintyFresh toothpaste. From a sample of 181 dentists, how unusual would it be to have more than 123 of them recommend MintyFresh toothpaste? Is the success-failure condition of the Central Limit Theorem satisfied? Yes. Both np and n(1 − p) are ≥ 10. - No. Either np < 10 or n(1 − p) < 10. The Central Limit Theorem tells us that the distribution of sample proportions approximately follows a norm distribution with mean and standard deviation Given this knowledge, calculate the z-score of this observation.

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Question 10
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Suppose that 6 out of 10 dentists recommend MintyFresh toothpaste. From a sample of 181 dentists, how
unusual would it be to have more than 123 of them recommend MintyFresh toothpaste?
Is the success-failure condition of the Central Limit Theorem satisfied?
Yes. Both np and n(1 − p) are ≥ 10.
-
No. Either np < 10 or n(1 − p) < 10.
The Central Limit Theorem tells us that the distribution of sample proportions approximately follows a normal
distribution with mean
and standard deviation
Given this knowledge, calculate the z-score of this observation.
Round answer to 4 decimal places.
Is this an unusual observation? (More than 2 standard deviations from the mean) Is it unlikely to sample 181
dentists and find 123 of them recommending Mintyfresh?
Yes.
O No.
Recall that, from the 68-95-99.7 Rule, 5 percent of observations fall more than 2 SDs from the mean. So, an
unusual observation means there is at most a 5% chance of this happening by random variation.
Transcribed Image Text:Question 10 > Suppose that 6 out of 10 dentists recommend MintyFresh toothpaste. From a sample of 181 dentists, how unusual would it be to have more than 123 of them recommend MintyFresh toothpaste? Is the success-failure condition of the Central Limit Theorem satisfied? Yes. Both np and n(1 − p) are ≥ 10. - No. Either np < 10 or n(1 − p) < 10. The Central Limit Theorem tells us that the distribution of sample proportions approximately follows a normal distribution with mean and standard deviation Given this knowledge, calculate the z-score of this observation. Round answer to 4 decimal places. Is this an unusual observation? (More than 2 standard deviations from the mean) Is it unlikely to sample 181 dentists and find 123 of them recommending Mintyfresh? Yes. O No. Recall that, from the 68-95-99.7 Rule, 5 percent of observations fall more than 2 SDs from the mean. So, an unusual observation means there is at most a 5% chance of this happening by random variation.
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