Suppose that 5 J of work is needed to stretch a spring from its natural length of 36 cm to a length of 56 cm. (a) How much work is needed to stretch the spring from 40 cm to 48 cm? (Round your answer to two decimal places.) 6.4 X J (b) How far beyond its natural length will a force of 10 N keep the spring stretched? (Round your answer one decimal place.) 0.5 X cm

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A: We see that, 312 : 212=72 : 52=7 : 5=1.4 : 1

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Q: 10

A: The area of the entire triangle is,  (5+3)(2+10)/2 = 48 square feet

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A: here l bisector is given  this is the question of geometry further calculation is given below

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A: Given: diameterD=16inches We know that distanced travel in n revolutions is given by d=nπD…

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