Suppose that 20% of the residents in a certain state support an increase in the property tax. Anopinion poll will randomly sample 400 state residents and will then compute the proportion in thesample that support a property tax increase.How likely is the resulting sample proportion to be within .04 of the true proportion (i.e., between.16 and .24)?(Hint: Use the sampling distribution of the sample proportion in this case.)O It is certain that the resulting sample proportion will be within .04 of the true proportion.O There is roughly a 99.7% chance that the resulting sample proportion will be within .04 of thetrue proportion.O There is roughly a 95% chance that the resulting sample proportion will be within .04 of thetrue proportion.O There is roughly a 68% chance that the resulting sample proportion will be within .04 of thetrue proportion.

Given info: Suppose 20% of the residents in a certain state support an increase in the property tax.…

Answered: Suppose that 20% of the residents in a…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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A mayor running for re-election claims that during his term, average municipal taxes have fallen by $125. A conscientious statistician wants to test this claim. He surveys 37 of his neighbors and finds that their taxes decreased (in dollars) as follows: 121, 139, 121, 125, 118, 145, 141, 91, 127, 136, 144, 154, 131, 139, 139, 125, 108, 130, 125, 106, 137, 148, 154, 134, 137, 112, 96, 114, 114, 126, 133, 129, 94, 129, 148, 163, 121 The statistician assumes a population standard deviation of $19. Do you think the statistician should reject the mayor's claim? Why or why not? Step 1: State the hypothesis. ?v= Step 2: Determine the Features of the Distribution of Point Estimates Using the Central Limit Theorem. By the Central Limit Theorem, we know that the point estimates are [Select an answer with distribution mean and distribution standard deviation Step 3: Assuming the Claim is True, Find the Probability of Obtaining the Point Estimate. P? ✓ ? ♥ = P(? ? ♥
A researcher belleves that 52% of people who grew up as the only child have an IQ score over 100. However, unknown to the researcher, this figure is actually 50%, which is the same as in the general population. To attempt to find evidence for the claim, the researcher is going to take a random sample of 400 people who grew up as the only child. Let p be the proportion of people in the sample with an IQ score above 100. Answer the following. (If necessary, consult a list of formulas.) (a) Find the mean of p. (b) Find the standard deviation of p. (c) Compute an approximation for P(p 20.52), which is the probability that there will be 52% or more people with IQ Scores over 100 in the sample. Round your answer to four decimal places. 2022 acer
According to Pew Research Center surveys, 79% of U.S. adults were using the Internet in January 2011 and 83% were using it in January 2012 (USA TODAY, January 26, 2012). Suppose that these percentages are based on random samples of 1720 U.S. adults in January 2011 and 1970 in January 2012. a. Let p, and p, be the proportions of all U.S. adults who were using the Internet in January 2011 and January 2012, respectively. Construct a 95% confidence interval for p, - P2- Round your answers to three decimal places. to i
In a Gallup poll of 1236 adult respondents, 6% said that bad luck follows breaking a mirror. That percentage has a margin of error of 1.5 percentage points. Why is it misleading to state that the percentage is 6% with a margin of error of 1.5%?
Statistics Question
A researcher wants to determine the percentage of American teenagers who send or receive text messages while doing homework. Which of the following techniques would likely be the MOST efficient way of obtaining an accurate estimate for this percentage? 1. Randomly select teenagers from the list of all teenage students in every state in America and mail surveys to those teens, asking them if they send or receive text messages while doing homework. 2. Send a survey to every teenager in America and ask them if they send or receive text messages while doing homework. 3. Randomly select teenagers from the list of all teenage students in one state and mail surveys to those teens, asking them if they send or receive text messages while doing homework.
Sleep apnea is a condition in which the sufferers stop breathing momentarily while they are asleep. This condition results in lack of sleep and extreme fatigue during waking hours. A current estimate is that 11.911.9 million out of the 312.7312.7 million Americans suffer from sleep apnea, or approximately 3.8%3.8%. A safety commission is concerned about the percentage of commercial truck drivers who suffer from sleep apnea. They do not have any reason to believe that it would be higher or lower than the population’s percentage. To test the claim that the percentage of commercial truck drivers who suffer from sleep apnea is not 3.8%3.8%, a simple random sample of 347347 commercial truck drivers is examined by a medical expert, who concludes that 66 suffer from sleep apnea. Does this evidence support the claim that the percentage of commercial truck drivers who suffer from sleep apnea is not 3.8%3.8%? Use a 0.020.02 level of significance. Step 3 of 4 : Find the p-value. Round…
5. 43% of the students in a school are boys. If there are 399 girls in the school, what is the entire population of the school? [2]
The state education commission wants to estimate the fraction of tenth grade students that have reading skills at or below the eighth grade level. Step 1 of 2: Suppose a sample of 333 tenth graders is drawn. Of the students sampled, 260 read above the eighth grade level. Using the data, estimate the proportion of tenth graders reading at or below the eighth grade level. Enter your answer as a fraction or a decimal number rounded to three decimal places. Step 2 of 2: Suppose a sample of 333 tenth graders is drawn. Of the students sampled, 260 read above the eighth grade level. Using the data, construct the 80% confidence interval for the population proportion of tenth graders reading at or below the eighth grade level. Round your answers to three decimal places.
Random samples of students at 107 four-year colleges were interviewed several times since 1998. Of the students who reported drinking alcohol, the percentage who reported bingeing at least three times within the past two weeks was 41.1% of 336 students in 1998 and 21.6% of 843 students in 2004. a. Estimate the difference between the proportions in 2004 and 1998, and interpret. b. Find the standard error for this difference. Interpret it. c. Define the two relevant population parameters to compare in the context of this exercise. d. Construct and interpret a 90% confidence interval to estimate the true difference. e. State the assumptions for the confidence interval in part d to be valid. ... A. The number of students in the population in 2004 who reported drinking alcohol that binged at least three times within the past two weeks. B. The proportion of the student population in 1998 who reported drinking alcohol that binged at least three times within the past two weeks. C. The number…
A mayor running for re-election claims that during his term, average municipal taxes have fallen by $150. A conscientious statistician wants to test this claim. She surveys 45 of her neighbors and finds that their taxes decreased (in dollars) as follows: 149, 135, 147, 147, 160, 146, 165, 144, 142, 159, 138, 185, 143, 164, 143, 154, 163, 151, 171, 156, 133, 145, 180, 172, 166, 167, 149, 144, 154, 172, 138, 168, 179, 151, 131, 165, 114, 140, 162, 151, 136, 152, 157, 154, 136 The statistician assumes a population standard deviation of $13. Do you think the statistician should reject the mayor's claim? Why or why not? Step 1: State the hypothesis. ? Step 2: Determine the Features of the Distribution of Point Estimates Using the Central Limit Theorem. By the Central Limit Theorem, we know that the point estimates are [Select an answer distribution mean with and distribution standard deviation Step 3: Assuming the Claim is True, Find the Probability of Obtaining the Point Estimate. P? ✓ ? ✓…
There are 435 seats in a nation's House of Representatives. The number of representatives per state is calculated using a statistical formula determined by law, but allocation is roughly proportionate to population. In 2010, the nation's population was estimated to be 309.1 million. The state's population was estimated at 26.1 million. How many representatives would you expect to be assigned to the state? Suppose the state actually has 34 representatives. Compare this with the expected number of representatives from the state.

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