Suppose that 146 out of a random sample of 200 letters mailed in the United States were delivered the day after they were mailed. Based on this, compute a 99% confidence interval for the proportion of all letters mailed in the United States that were delivered the day after they were mailed. Then find the lower limit and upper limit of the 99% confidence interval. Carry your intermediate computations to at least three decimal places. Round your answers to two decimal places

Q: test. It was found that 80 of them scored higher than 100. Based on this, compute a 95% confidence…

A: According to the given information in this question We need to construct 95% confidence interval

Q: In a sample of 300 adults, 228 had children. Construct a 90% confidence interval for the true…

A: Given C=90% Confidence level X=228 N=300

Q: If n=32, ¯xx¯(x-bar)=31, and s=14, construct a confidence interval at a 95% confidence level. Assume…

A: Given: x¯=31n=32s=1495% confidence level

Q: Out of a sample of 600 adults aged 18 to 30, 162 still lived with their parents. Based on this,…

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Q: In a sample of 310 adults, 205 had children. Construct a 99% confidence interval for the true…

A: Given data, n=310 x=205 p=x/n=205/310=0.661 z-value at 99% confidence is Zc=2.576

Q: If n=30, ¯xx¯(x-bar)=43, and s=16, construct a confidence interval at a 98% confidence level. Assume…

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Q: If n = 15, 43, and s = 9, construct a confidence interval at a 98 % confidence level. Assume the…

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Q: If n=16, ¯xx¯(x-bar)=46, and s=12, construct a confidence interval at a 95% confidence level. Assume…

A: Given n=16 x=46 s=12 CL=95% Data is normally distributed

Q: In a sample of 400 college seniors, 340 responded positively when asked if they have spring fever.…

A: Proprotion is the measure that explain the ratio of favorable cases. It is also equal to probability…

Q: In a sample of 350 adults, 277 had children. Construct a 99% confidence interval for the true…

A: The sample size, i.e., the sampled number of adults, n=350.The sampled number of adults with…

Q: If n=22, ¯xx¯(x-bar)=45, and s=4, construct a confidence interval at a 90% confidence level. Assume…

A: Ans -   Given the level of confidence interval   90 %                      Then   α = 1 - 0.90 =…

Q: We wish to estimate what percent of adult residents in a certain county are parents. Out of 600…

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Q: If n=15, ¯xx¯(x-bar)=30, and s=2, construct a confidence interval at a 98% confidence level. Assume…

A: Given Sample size n = 15  degree of freedom = n-1 =14 x the level of confidence interval   98 %…

Q: Out of 240 sample students surveyed, 187 students are planning to take classes during the…

A: We have given that the sample size n=240 and favourable cases X=187. Sample proportion p^ = X/n.

Q: If n = 28, ¯xx¯ = 49, and s = 19, construct a confidence interval at a 90% confidence level. Assume…

A: Given information- Sample size, n = 28 Sample mean, x-bar = 49 Sample standard deviation, s = 19…

Q: Suppose that the a college wants to have an idea of the average SAT score of the incoming freshman…

A: The confidence level is 0.90, the standard deviation is 310 and margin of error E is 50.

Q: If n = 16, 7 = 43, and s = 17, construct a confidence interval at a 98% confidence level. Assume the…

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Q: If n=19, ¯xx¯(x-bar)=37, and s=13, construct a confidence interval at a 99% confidence level. Assume…

A:

Q: If n=22, ¯xx¯(x-bar)=46, and s=8, construct a confidence interval at a 98% confidence level. Assume…

A: It is given that mean and standard deviation are 46 and 8, respectively.

Q: How much do wild mountain lions weigh? Adult wild mountain lions (18 months or older) captured and…

A: From the given information. We want to find sample mean, SD and 75 percent confidence interval.

Q: n=31, ¯xx¯(x-bar)=30, and s=5, construct a confidence interval at a 98% confidence level. Assume the…

A:

Q: A researcher wanted to check whether the percentage of Canadian adults with obesity has decreased in…

A: Number of Canadian adults in 2005= 75 Number of Canadian adults in 2009 = 120   significance level =…

Q: In a sample of 500 adults, 340 had children. Construct a 99% confidence interval for the true…

A: Proportion is almost similar to the concept of probability. Proportion is a fraction of a population…

Q: Scientists tested each in a sample of 6 alleles of antigen-produced protein for level of peptide.…

A: The sample size n=6 The sample mean x¯=1.54 The sample standard deviation s=0.13 The confidence…

Q: In a sample of 290 adults, 191 had children. Construct a 95% confidence interval for the true…

A: 0.604 < p < 0.713 Explanation:Approach to solving the question:To construct a 95% confidence…

Q: In a sample of 240 adults, 180 had children. Construct a 95% confidence interval for the true…

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Q: In a sample of 290 adults, 261 had children. Construct a 95% confidence interval for the true…

A: Given : Sample Size, n = 290 Number of successes, x = 261

Q: In a random sample of 500 Americans, 50% indicated that they have a cat for a pet. Estimate with 95%…

A: Given information

Q: In a sample of 350 adults, 277 had children. Construct a 99% confidence interval for the true…

A: Sample size, Number of adults having children, Confidence level is .

Q: If n=13, ¯x(x-bar)=44, and s=3, construct a confidence interval at a 99% confidence level. Assume…

A: Here, n is 13, x-bar is 44, and s is 3. Critical value: Using Excel formula…

Q: If n=19, ¯xx¯=40, and s=7, construct a confidence interval at a 99% confidence level. Assume the…

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Q: If n=15, ¯xx¯(x-bar)=40, and s=9, construct a confidence interval at a 98% confidence level. Assume…

A:

Q: We wish to estimate what percent of adult residents in a certain county are parents. Out of 100…

A: According to the given information, we have Out of 100 adult residents sampled, 88 had kids. 99%…

Q: If n=15, ¯xx¯(x-bar)=33, and s=19, construct a confidence interval at a 80% confidence level. Assume…

A: Given' :  sample mean xbar=33  sample size n=15  sample standard deviations s=14  then to find 80%…

Q: Suppose that 18% of a random sample of 2307 Miami residents said that they will donate blood in…

A: The sample proportion is given as 0.18. The sample size is given as 2307. The two-tailed z-critical…

Q: If n=28, ¯x(x-bar)=32, and s=11, construct a confidence interval at a 95% confidence level. Assume…

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Q: If n=13, ¯xx¯(x-bar)=37, and s=9, construct a confidence interval at a 80% confidence level. Assume…

A: Givenn =13x = 37s=9confidence interval =80%

Q: Can you please write B up in writing as it is incorrect but I think it's because it's been converted…

A: f(x) = 3(x-1)^2, 0<x<1

Q: Elvin wants to know how the school views him as their leader. He asked his friend, Marcus, to…

A:

Q: In a sample of 470 adults, 306 had children. Construct a 99% confidence interval for the true…

A:

Q: 15, ¯xx¯(x-bar)=39, and s=11, construct a confidence interval at a 95% confidence level. Assume the…

A: Sample size (n) =15 Sample mean (x¯)=39 Sample standard deviation (s)=11 Confidence level (C)=95%…

Q: In a sample of 460 adults, 281 had children. Construct a 90% confidence interval for the true…

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Q: Now you are interested in the percent of dogs that were neutered in your sample. For 40 dogs, 30 of…

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Q: Suppose you compute a confidence interval with a sample size of 25. What will happen to the…

A: See the handwritten solution

Q: f n=29, x¯(x-bar)=31, and s=8, construct a confidence interval at a 90% confidence level. Assume the…

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Estimation

A new framework of data analysis where the new statistical methods are used for interpreting the results and analyzing the data is known as estimation in statistics.