Suppose that 12% of the families in a certain community have no children, 22% have one, 34% have two, and 32% have three children. Suppose further that each child is equally likely (and independently) to be a boy or a girl. If a family is chosen at random from this community, then find the probability of P(B-0,G=0)where B is the number of boys, G is the number of girls.OPB-0,G-0)-0.1200OPB 0,G-0) 0.6071O P(B-0,G=0)=0,1169OP(B-0,G-0) 0.1155

Answer:- According to the given information, P( no children) = 12% = 0.1200 P( one children) = 22%…

Answered: Suppose that 12% of the families in a…

A First Course in Probability (10th Edition)

10th Edition

ISBN:9780134753119

Author:Sheldon Ross

Publisher:Sheldon Ross

Chapter1: Combinatorial Analysis

Section: Chapter Questions

Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...

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