Suppose that 1 1/2 1/3 [1/5 is a solution of Ax = b for some vector b. Find a second solution x of the equation Ax = b for which the third component is 0 (i.e. so that x3 = 0).

Q: -3x+y=-17 -x+y=-5 substitution method.

A: Solve the given equation

Q: Solve for v -8v-19= -5(v+5)

A: To find: -

Q: How would this be done in substitution method: 2x + 3y = 8 -4x - 6y = 6

A: We will use simple steps of substitution to  solve this.

Q: Solve the equation их + иу + и %3D0, u(х,0) — х?.

A: Partial differential equation

Q: 8y

A:

Q: Solve for x and check: V4+ 2x = -2 3 %3D

A: Explanation: Given that: 4+2x3=-2 Concept: Cubing on both side 4+2x=(-2)3…

Q: 2x + y = 5 X - y = 1 Use substitution method

A:

Q: Why is x=-4 not a solution for the highlighted problem?   Thanks.

A:

Q: 2 cos (3xtZl) = VZ 0°EX Ę 360 2(05

A: 2cos3x+21=2

Q: VZ A2 + B2 =0 A2 + VZB2 + C2=0 B2 + VZ Cz = 0

A: We have to solve the given system of equation.

Q: Solve the formula 5x + 2y = 14 for y when x = 8. y =        Solve the formula 5x + 2y = 14 for y in…

A:

Q: )Use the discriminant to determine the number of real solutions 4 9x -4x+-0 9. %3D

A:

Q: gift has the dimensions are 50 cm times 35 cm times 5 cm. You have wrapping paper with dimensions of…

A: Consider the dimensions of a gift are : Length=50 cm Breadth=35 cm height=5 cm