Suppose T: P3-M22 is an isomorphism whose action on a basis for P3 is as follows: 33 T(x³ ) =| 3 3 -6 -6 0 4 T(2x2+x) = 1 -2 -1 Т(3) - T(x3 +x² +x+1)= -6 -12 1 Find the inverse transformation T1 and give its action on a general matrix, using x as the variable for the polynomial and p, q, r, and s as constants. Use the A character to indicate an exponent e.g. рx 2-qх+r.
Suppose T: P3-M22 is an isomorphism whose action on a basis for P3 is as follows: 33 T(x³ ) =| 3 3 -6 -6 0 4 T(2x2+x) = 1 -2 -1 Т(3) - T(x3 +x² +x+1)= -6 -12 1 Find the inverse transformation T1 and give its action on a general matrix, using x as the variable for the polynomial and p, q, r, and s as constants. Use the A character to indicate an exponent e.g. рx 2-qх+r.
Algebra and Trigonometry (6th Edition)
6th Edition
ISBN:9780134463216
Author:Robert F. Blitzer
Publisher:Robert F. Blitzer
ChapterP: Prerequisites: Fundamental Concepts Of Algebra
Section: Chapter Questions
Problem 1MCCP: In Exercises 1-25, simplify the given expression or perform the indicated operation (and simplify,...
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The image with red color is example . Please solve the other one

Transcribed Image Text:Suppose T: P3-→M22 is an isomorphism whose action on a basis for P3 is as follows:
0 4
T(x3+x²+x+1) =
1 -2
-1 6
3 3
T(x³ ) =
3 3
T(3) =
T(2x²+x) =
-6 -12
-1
Find the inverse transformation T- and give its action on a general matrix, using x as the variable for the polynomial and p, q, r, and s as constants. Use the 'A' character to indicate an exponent,
e.g. px^2-qx+r.
![Suppose T: P2-R° is an isomorphism whose action on a basis for P2 is as follows:
1
-3
2
T(x+1)= 2 T(3x²+3x+3)=| 0
T(-x2-1) = |1
2
Find the inverse transformation T1 and give its action on a general vector, using x as the
variable for the polynomial and p, q, and r as constants. Use the 'A' character to indicate an
exponent, e.g. px^2-qx+r.
= (-4p-29-2r)x²+
p-+tp+q)
The correct answer is:
1
T1
글기자2+(-p+r]x+(-p+q)](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F4703214b-7b6d-48dc-8fec-73bc2badaa48%2Fbcc828bf-463d-43f6-a5dc-786949905f4c%2F1pipfci_processed.png&w=3840&q=75)
Transcribed Image Text:Suppose T: P2-R° is an isomorphism whose action on a basis for P2 is as follows:
1
-3
2
T(x+1)= 2 T(3x²+3x+3)=| 0
T(-x2-1) = |1
2
Find the inverse transformation T1 and give its action on a general vector, using x as the
variable for the polynomial and p, q, and r as constants. Use the 'A' character to indicate an
exponent, e.g. px^2-qx+r.
= (-4p-29-2r)x²+
p-+tp+q)
The correct answer is:
1
T1
글기자2+(-p+r]x+(-p+q)
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