Suppose S and T are mutually exclusive events, P(S) = 20%, and P(T) = 22%. Find P(S or 7). a b C d 2% 440% 42% 4.4%

MATLAB: An Introduction with Applications
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Author:Amos Gilat
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**Example Probability Question**

_Suppose S and T are mutually exclusive events, P(S) = 20%, and P(T) = 22%. Find P(S or T)._

**Options:**
- a) 2%
- b) 440%
- c) 42%
- d) 4.4%

**Explanation:**
Since S and T are mutually exclusive events, the probability of either event S or event T occurring (denoted as P(S or T)) is calculated using the formula: 

\[ P(S \text{ or } T) = P(S) + P(T) \]

Given values:
- P(S) = 20%
- P(T) = 22%

Calculating P(S or T):
\[ P(S \text{ or } T) = 20\% + 22\% = 42\% \]

Therefore, the correct answer is:

- c) 42%
Transcribed Image Text:**Example Probability Question** _Suppose S and T are mutually exclusive events, P(S) = 20%, and P(T) = 22%. Find P(S or T)._ **Options:** - a) 2% - b) 440% - c) 42% - d) 4.4% **Explanation:** Since S and T are mutually exclusive events, the probability of either event S or event T occurring (denoted as P(S or T)) is calculated using the formula: \[ P(S \text{ or } T) = P(S) + P(T) \] Given values: - P(S) = 20% - P(T) = 22% Calculating P(S or T): \[ P(S \text{ or } T) = 20\% + 22\% = 42\% \] Therefore, the correct answer is: - c) 42%
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