Suppose P4(x) (part 1 of 4) = 2-5x + 2x². - 4x³ + 5x¹ 2. f(0) = 3 3. f(0) 4. f(0) 5. f(0) = -2 = 4 = 2 (part 2 of 4) (ii) What is the value of f(³) (0)? 4 3 1. f(³) (0) 2. f(³) (0) 3. f(³) (0) 4. f(³) (0) 5. f(³) (0) = = 24 = -24 = -4 4 = 1/ 3 (part 3 of 4) (iii) Use p4 to estimate the value of f(0.1) 1. f(0.1) 1.7165 2. f(0.1) 1.4165 3. f(0.1) 1.5165 4. f(0.1) 1.8165 5. f(0.1) 1.6165

Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Question
(part 1 of 4)
Suppose
P4(x)
is the degree 4 Taylor polynomial centered at
0 for some function f.
(i) What is the value of f(0)?
1. f(0)
X =
= 2
==
-3
-
5x + 2x² - 4x³ +5x²
2. f(0) = 3
3. f(0) = -2
4. f(0) = 4
5. f(0) = 2
(part 2 of 4)
(ii) What is the value of ƒ(³)(0)?
4
1. ƒ(³) (0)
3
2. f(³) (0) = 24
3. f(³) (0) = -24
4. f(³) (0)
= –4
4
5. ƒ(³) (0) = 1/3
(part 3 of 4)
(iii) Use p4 to estimate the value of f(0.1).
1. f(0.1) 1.7165
2. f(0.1)≈ 1.4165
3. f(0.1)≈ 1.5165
4. f(0.1)≈ 1.8165
5. f(0.1) 1.6165
Transcribed Image Text:(part 1 of 4) Suppose P4(x) is the degree 4 Taylor polynomial centered at 0 for some function f. (i) What is the value of f(0)? 1. f(0) X = = 2 == -3 - 5x + 2x² - 4x³ +5x² 2. f(0) = 3 3. f(0) = -2 4. f(0) = 4 5. f(0) = 2 (part 2 of 4) (ii) What is the value of ƒ(³)(0)? 4 1. ƒ(³) (0) 3 2. f(³) (0) = 24 3. f(³) (0) = -24 4. f(³) (0) = –4 4 5. ƒ(³) (0) = 1/3 (part 3 of 4) (iii) Use p4 to estimate the value of f(0.1). 1. f(0.1) 1.7165 2. f(0.1)≈ 1.4165 3. f(0.1)≈ 1.5165 4. f(0.1)≈ 1.8165 5. f(0.1) 1.6165
2. ƒ'(-0.1) ≈ -5.84
3. f'(-0.1) ≈ -5.74
4. f'(-0.1) ≈ −5.64
5. f'(-0.1) -5.54
(part 4 of 4)
(iv) Use p4 to estimate the value of ƒ'(-0.1).
1. ƒ'(-0.1) ≈ -5.94
Transcribed Image Text:2. ƒ'(-0.1) ≈ -5.84 3. f'(-0.1) ≈ -5.74 4. f'(-0.1) ≈ −5.64 5. f'(-0.1) -5.54 (part 4 of 4) (iv) Use p4 to estimate the value of ƒ'(-0.1). 1. ƒ'(-0.1) ≈ -5.94
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