Suppose P = (0, – 1, 6) and PQ = (9, 2, – 4). and ( Enter an integer or decimal number (more.] Two more points on the line PQ are , ). (Enter the coordinates of two other points on the line PQ)

Algebra and Trigonometry (6th Edition)
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ChapterP: Prerequisites: Fundamental Concepts Of Algebra
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Problem 1MCCP: In Exercises 1-25, simplify the given expression or perform the indicated operation (and simplify,...
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Linear algebra Question:

Suppose P=(0,-1,6) and −−→PQ(line)=⟨9,2,−4⟩.

Two more points on the line PQPQ are ((, , )) and (( , , , )).

(Enter the coordinates of two other points on the line PQPQ)

---

### Sample Problem: Identifying Points on a Line in 3D Space

Suppose \( P = (0, -1, 6) \) and \(\overrightarrow{PQ} = (9, 2, -4) \).

**Task:**

Identify two more points on the line \( P Q \).

**Solution:**

Two more points on the line \( P Q \) are:
- \( ( \_ , \_ , \_ ) \)
- \( ( \_ , \_ , \_ ) \)

(Enter the coordinates of two other points on the line \( P Q \).)

---

### Detailed Description

We are given a point \( P \) and a direction vector \(\overrightarrow{PQ}\). To find more points on the line, we can use the parametric form of the line equation. The parametric form of the line can be written as:

\[ \mathbf{r}(t) = \mathbf{P} + t \cdot \overrightarrow{PQ} \]

where \(\mathbf{P}\) is the starting point, \( t \) is a scalar parameter, and \(\overrightarrow{PQ}\) is the direction vector pointing from \( P \) to \( Q \).

For specific values of \( t \), calculate new points on the line:

1. **First Additional Point:**

   Let \( t = 1 \),

   \[
   \mathbf{r}(1) = (0, -1, 6) + 1 \cdot (9, 2, -4) = (0 + 9, -1 + 2, 6 - 4) = (9, 1, 2)
   \]

2. **Second Additional Point:**

   Let \( t = 2 \),

   \[
   \mathbf{r}(2) = (0, -1, 6) + 2 \cdot (9, 2, -4) = (0 + 18, -1 + 4, 6 - 8) = (18, 3, -2)
   \]

Therefore, two more points on the line \( P Q \) are:

- \( (9, 1, 2) \)
- \( (18, 3, -2) \)

(Ensure you replace the blanks with the above-calculated coordinates
Transcribed Image Text:--- ### Sample Problem: Identifying Points on a Line in 3D Space Suppose \( P = (0, -1, 6) \) and \(\overrightarrow{PQ} = (9, 2, -4) \). **Task:** Identify two more points on the line \( P Q \). **Solution:** Two more points on the line \( P Q \) are: - \( ( \_ , \_ , \_ ) \) - \( ( \_ , \_ , \_ ) \) (Enter the coordinates of two other points on the line \( P Q \).) --- ### Detailed Description We are given a point \( P \) and a direction vector \(\overrightarrow{PQ}\). To find more points on the line, we can use the parametric form of the line equation. The parametric form of the line can be written as: \[ \mathbf{r}(t) = \mathbf{P} + t \cdot \overrightarrow{PQ} \] where \(\mathbf{P}\) is the starting point, \( t \) is a scalar parameter, and \(\overrightarrow{PQ}\) is the direction vector pointing from \( P \) to \( Q \). For specific values of \( t \), calculate new points on the line: 1. **First Additional Point:** Let \( t = 1 \), \[ \mathbf{r}(1) = (0, -1, 6) + 1 \cdot (9, 2, -4) = (0 + 9, -1 + 2, 6 - 4) = (9, 1, 2) \] 2. **Second Additional Point:** Let \( t = 2 \), \[ \mathbf{r}(2) = (0, -1, 6) + 2 \cdot (9, 2, -4) = (0 + 18, -1 + 4, 6 - 8) = (18, 3, -2) \] Therefore, two more points on the line \( P Q \) are: - \( (9, 1, 2) \) - \( (18, 3, -2) \) (Ensure you replace the blanks with the above-calculated coordinates
**Title: Determining Coordinates on a Line in 3D Space**

**Instructions:**

Given two points, \( P \) and \( Q \), in a 3-dimensional space, we want to identify another point on the line passing through both \( P \) and \( Q \).

**Problem Statement:**

Suppose \( P = (-3, 5, -4) \) and \( Q = (5, 2, -10) \).

**Task:**

Calculate the coordinates of another point on the line \( PQ \).

**Answer Input:**

Another point on the line \( PQ \) is \( \left( \quad , \quad , \quad \right) \).

*(Enter the coordinates of another point on the line \( PQ \))*

**Explanation:**

- The coordinates \( P(x_1, y_1, z_1) = (-3, 5, -4) \) and \( Q(x_2, y_2, z_2) = (5, 2, -10) \) represent two distinct points on a line in 3D space.
- To find another point on this line, we can use parametric equations or simply extend the line segment using the directional vector from \( P \) to \( Q \). The vector from \( P \) to \( Q \) is given by:

  \[
  \overrightarrow{PQ} = Q - P = (5 - (-3), 2 - 5, -10 - (-4)) = (8, -3, -6)
  \]

- By adding a scalar multiple of \(\overrightarrow{PQ}\) to \(P\), we can find another point on the line. For example, for the parameter \( t = 1 \):

  \[
  R = P + t \cdot \overrightarrow{PQ} = (-3, 5, -4) + 1 \cdot (8, -3, -6) = (-3 + 8, 5 - 3, -4 - 6) = (5, 2, -10)
  \]

  Confirming \(Q\). To get a different point, you can try \( t = \frac{1}{2} \):

  \[
  R = P + \frac{1}{2} \cdot \overrightarrow{PQ} =
Transcribed Image Text:**Title: Determining Coordinates on a Line in 3D Space** **Instructions:** Given two points, \( P \) and \( Q \), in a 3-dimensional space, we want to identify another point on the line passing through both \( P \) and \( Q \). **Problem Statement:** Suppose \( P = (-3, 5, -4) \) and \( Q = (5, 2, -10) \). **Task:** Calculate the coordinates of another point on the line \( PQ \). **Answer Input:** Another point on the line \( PQ \) is \( \left( \quad , \quad , \quad \right) \). *(Enter the coordinates of another point on the line \( PQ \))* **Explanation:** - The coordinates \( P(x_1, y_1, z_1) = (-3, 5, -4) \) and \( Q(x_2, y_2, z_2) = (5, 2, -10) \) represent two distinct points on a line in 3D space. - To find another point on this line, we can use parametric equations or simply extend the line segment using the directional vector from \( P \) to \( Q \). The vector from \( P \) to \( Q \) is given by: \[ \overrightarrow{PQ} = Q - P = (5 - (-3), 2 - 5, -10 - (-4)) = (8, -3, -6) \] - By adding a scalar multiple of \(\overrightarrow{PQ}\) to \(P\), we can find another point on the line. For example, for the parameter \( t = 1 \): \[ R = P + t \cdot \overrightarrow{PQ} = (-3, 5, -4) + 1 \cdot (8, -3, -6) = (-3 + 8, 5 - 3, -4 - 6) = (5, 2, -10) \] Confirming \(Q\). To get a different point, you can try \( t = \frac{1}{2} \): \[ R = P + \frac{1}{2} \cdot \overrightarrow{PQ} =
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