Suppose Nate wins 34% of all checker games. (a) What is the probability that Nate wins two checker games in a row? (b) What is the probability that Nate wins six checker games in a row? (c) When events are independent, their complements are independent as well. Use this result to determine the probability that Nate wins six checker games in a row, but does not win seven in a row. (a) The probability that Nate wins two checker games in a row is (Round to four decimal places as needed.) (b) The probability that Nate wins six checker games in a row is (Round to four decimal places as needed.) (c) The probability that Nate wins six checker games in a row, but does not win seven in a row is (Round to four decimal places as needed.)

Holt Mcdougal Larson Pre-algebra: Student Edition 2012
1st Edition
ISBN:9780547587776
Author:HOLT MCDOUGAL
Publisher:HOLT MCDOUGAL
Chapter11: Data Analysis And Probability
Section11.9: Independent And Dependent Events
Problem 3C
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### Probability Questions on Sequential Wins in Checkers

#### Problem Scenario:
Suppose Nate wins 34% of all checker games.

#### Questions:
(a) What is the probability that Nate wins two checker games in a row?

(b) What is the probability that Nate wins six checker games in a row?

(c) When events are independent, their complements are independent as well. Use this result to determine the probability that Nate wins six checker games in a row, but does not win seven in a row.

---

### Solution:

**(a)** The probability that Nate wins two checker games in a row is: 

\[ \boxed{\hspace{2cm}}  \]

*(Round to four decimal places as needed.)*

**(b)** The probability that Nate wins six checker games in a row is:

\[ \boxed{\hspace{2cm}}  \]

*(Round to four decimal places as needed.)*

**(c)** The probability that Nate wins six checker games in a row, but does not win seven in a row is:

\[ \boxed{\hspace{2cm}}  \]

*(Round to four decimal places as needed.)*

#### Explanation:
1. **Probability of Consecutive Wins:**
   - The probability of winning a single game is 34% or 0.34.
   - The events are independent, so the probability of Nate winning multiple games in a row is the product of the probabilities of each individual game win.
   
2. **(a) Two Games in a Row:**
   - Probability (2 wins) = \((0.34)^2\).
   
3. **(b) Six Games in a Row:**
   - Probability (6 wins) = \((0.34)^6\).
   
4. **(c) Six Wins Followed by a Loss:**
   - First, calculate the probability of six wins, as in (b).
   - Then, multiply it by the probability of a loss (which is the complement of the win probability).
   - Probability of a loss = \(1 - 0.34 = 0.66\).
   - Probability (6 wins followed by a loss) = \((0.34)^6 \times 0.66\).

Please fill in the calculations as necessary and round to four decimal places as indicated.

---

**Graph Explanation:**
There are no graphs present in this problem scenario. The task involves calculations based on
Transcribed Image Text:### Probability Questions on Sequential Wins in Checkers #### Problem Scenario: Suppose Nate wins 34% of all checker games. #### Questions: (a) What is the probability that Nate wins two checker games in a row? (b) What is the probability that Nate wins six checker games in a row? (c) When events are independent, their complements are independent as well. Use this result to determine the probability that Nate wins six checker games in a row, but does not win seven in a row. --- ### Solution: **(a)** The probability that Nate wins two checker games in a row is: \[ \boxed{\hspace{2cm}} \] *(Round to four decimal places as needed.)* **(b)** The probability that Nate wins six checker games in a row is: \[ \boxed{\hspace{2cm}} \] *(Round to four decimal places as needed.)* **(c)** The probability that Nate wins six checker games in a row, but does not win seven in a row is: \[ \boxed{\hspace{2cm}} \] *(Round to four decimal places as needed.)* #### Explanation: 1. **Probability of Consecutive Wins:** - The probability of winning a single game is 34% or 0.34. - The events are independent, so the probability of Nate winning multiple games in a row is the product of the probabilities of each individual game win. 2. **(a) Two Games in a Row:** - Probability (2 wins) = \((0.34)^2\). 3. **(b) Six Games in a Row:** - Probability (6 wins) = \((0.34)^6\). 4. **(c) Six Wins Followed by a Loss:** - First, calculate the probability of six wins, as in (b). - Then, multiply it by the probability of a loss (which is the complement of the win probability). - Probability of a loss = \(1 - 0.34 = 0.66\). - Probability (6 wins followed by a loss) = \((0.34)^6 \times 0.66\). Please fill in the calculations as necessary and round to four decimal places as indicated. --- **Graph Explanation:** There are no graphs present in this problem scenario. The task involves calculations based on
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