Suppose n is greater than, or equal to 2 and a natural number. If there is a pairwise disjoint set such as A1, A2, ..., An (which means that Ax∩Ay = 0 for all 1 ≤ x < y ≤ n) and the addition principle states that |A1UA2U...UAn|=|A1|+|A2|+...+|An|. Then prove the two-set version of the addition principle using a mathematical proof.
Suppose n is greater than, or equal to 2 and a natural number. If there is a pairwise disjoint set such as A1, A2, ..., An (which means that Ax∩Ay = 0 for all 1 ≤ x < y ≤ n) and the addition principle states that |A1UA2U...UAn|=|A1|+|A2|+...+|An|. Then prove the two-set version of the addition principle using a mathematical proof.
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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Question
Suppose n is greater than, or equal to 2 and a natural number. If there is a pairwise disjoint set such as A1, A2, ..., An (which means that Ax∩Ay = 0 for all 1 ≤ x < y ≤ n) and the addition principle states that |A1UA2U...UAn|=|A1|+|A2|+...+|An|. Then prove the two-set version of the addition principle using a mathematical proof.
Expert Solution
Step 1
The two-set version of the addition principle can be obtained from the given description and is as follows.
If A1 and A2 are two disjoint sets, then
| A1 U A2 | = |A1| + |A2|
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