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Suppose N = 11 and r = 4. Compute the hypergeometric probabilities for the following values of n and . If the calculations are not possible, please select "not possible" from below drop-downs, and enter 0 in fields. Round your answers, if necessary. a. n = 4, x = 2 (to 2 decimals). possible 0.51 b. n = 2, x = 2 (to 3 decimals). - Select your answer - c. n = 2, x = 0 (to 4 decimals). - Select your answer -

Suppose N = 11 and r = 4. Compute the hypergeometric probabilities for the following values of n and . If the calculations are not possible, please select "not possible" from below drop-downs, and enter 0 in fields. Round your answers, if necessary. a. n = 4, x = 2 (to 2 decimals). possible 0.51 b. n = 2, x = 2 (to 3 decimals). - Select your answer - c. n = 2, x = 0 (to 4 decimals). - Select your answer -

MATLAB: An Introduction with Applications
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
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Suppose N = 11 and r = 4. Compute the hypergeometric probabilities for the following values of n and . If the calculations are not possible, please select "not possible" from below drop-downs, and enter 0 in fields. Round your answers, if necessary. a. n = 4, x = 2 (to 2 decimals). possible 0.51 b. n = 2, x = 2 (to 3 decimals). Select your answer - c. n = 2, x = 0 (to 4 decimals). - Select your answer - d. n = 5, x = 3 (to 2 decimals). - Select your answer - e. n = 5, x = 5 (to 2 decimals). Select your answer -
Transcribed Image Text:Suppose N = 11 and r = 4. Compute the hypergeometric probabilities for the following values of n and . If the calculations are not possible, please select "not possible" from below drop-downs, and enter 0 in fields. Round your answers, if necessary. a. n = 4, x = 2 (to 2 decimals). possible 0.51 b. n = 2, x = 2 (to 3 decimals). Select your answer - c. n = 2, x = 0 (to 4 decimals). - Select your answer - d. n = 5, x = 3 (to 2 decimals). - Select your answer - e. n = 5, x = 5 (to 2 decimals). Select your answer -
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The probability mass function of hypergeometric distribution is as follows.

P(X=x)=CxrCn-xN-rCnN

N∈{0,1,2...}r∈{0,1,2...N}n∈{0,1,2..N}

The combination is as follows.

Cxn=n!(n-x)!x!

The factorial is as follows

n!=(n-1)×(n-2)×...×2×1

Given that,

N=11r=4

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