Suppose μ1 and μ2 are real average stopping distances at 50 mph of a certain type of car equipped with two different types of braking systems. Use the two-sample t test at the 0.01 significance level to test H0: (μ1 - μ2 = -10) vs. Ha: (μ1 - μ2 < -10) for the following data: m = 6 ; x̄ = 115,7 ; s1 = 5,03 ; n = 6 ; ȳ = 129,3 and s2 = 5,38 . After the calculations performed, it is possible to mark the alternative as correct: a) Test t = -1.25; the calculated degree of freedom v= 8.06; p-value = 0.03; therefore we reject H0 for the 0.05 significance level. b) Test t = 2.15; the calculated degree of freedom v= 9; p-value = 0.13; therefore we accept H0 for the 0.01 significance level. c) Test t = -1.20; the calculated degree of freedom v= 9.96; p-value = 0.130; therefore we accept H0 for the 0.01 significance level. d) Test t = -1.20; the calculated degree of freedom v= 9.96; p-value = 0.130; therefore we reject H0 for the 0.01 significance level. e) Test t = -1.25; the calculated deg
Suppose μ1 and μ2 are real average stopping distances at 50 mph of a certain type of car equipped with two different types of braking systems. Use the two-sample t test at the 0.01 significance level to test H0: (μ1 - μ2 = -10) vs. Ha: (μ1 - μ2 < -10) for the following data: m = 6 ; x̄ = 115,7 ; s1 = 5,03 ; n = 6 ; ȳ = 129,3 and s2 = 5,38 . After the calculations performed, it is possible to mark the alternative as correct:
a) Test t = -1.25; the calculated degree of freedom v= 8.06; p-value = 0.03; therefore we reject H0 for the 0.05 significance level.
b) Test t = 2.15; the calculated degree of freedom v= 9; p-value = 0.13; therefore we accept H0 for the 0.01 significance level.
c) Test t = -1.20; the calculated degree of freedom v= 9.96; p-value = 0.130; therefore we accept H0 for the 0.01 significance level.
d) Test t = -1.20; the calculated degree of freedom v= 9.96; p-value = 0.130; therefore we reject H0 for the 0.01 significance level.
e) Test t = -1.25; the calculated degree of freedom v= 8.06; p-value = 0.03; therefore we accept H0 for the 0.05 significance level.
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