Suppose for vectors u, v and w that – 3u + 5v + 2w = 0. What does this say about the set {u, v, w}? Answer: There is not enough information to determine whether the set is linearly independent or linearly dependent. O It is linearly independent It is linearly dependent
Suppose for vectors u, v and w that – 3u + 5v + 2w = 0. What does this say about the set {u, v, w}? Answer: There is not enough information to determine whether the set is linearly independent or linearly dependent. O It is linearly independent It is linearly dependent
Algebra and Trigonometry (6th Edition)
6th Edition
ISBN:9780134463216
Author:Robert F. Blitzer
Publisher:Robert F. Blitzer
ChapterP: Prerequisites: Fundamental Concepts Of Algebra
Section: Chapter Questions
Problem 1MCCP: In Exercises 1-25, simplify the given expression or perform the indicated operation (and simplify,...
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![### Linear Independence of Vectors
**Problem Statement:**
Suppose for vectors \( \vec{u} \), \( \vec{v} \), and \( \vec{w} \) that
\[ -3\vec{u} + 5\vec{v} + 2\vec{w} = \vec{0}. \]
What does this say about the set \( \{ \vec{u}, \vec{v}, \vec{w} \} \)?
**Answer:**
- There is not enough information to determine whether the set is linearly independent or linearly dependent.
- It is linearly independent.
- It is linearly dependent.
**Explanation:**
The equation provided is:
\[ -3\vec{u} + 5\vec{v} + 2\vec{w} = \vec{0}. \]
This represents a linear combination of vectors \( \vec{u} \), \( \vec{v} \), and \( \vec{w} \) resulting in the zero vector. The coefficients \(-3\), \(5\), and \(2\) are non-zero, indicating that a non-trivial linear combination of the vectors results in the zero vector. Therefore, the vectors \( \vec{u} \), \( \vec{v} \), and \( \vec{w} \) are linearly dependent.
_Selecting the correct answer:_
- It is linearly dependent.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F088399be-9a43-44b3-a949-bec438b8f98b%2F5f301a9f-8175-4485-89ca-2ff2a8d8c807%2Fx5v1g6d_processed.jpeg&w=3840&q=75)
Transcribed Image Text:### Linear Independence of Vectors
**Problem Statement:**
Suppose for vectors \( \vec{u} \), \( \vec{v} \), and \( \vec{w} \) that
\[ -3\vec{u} + 5\vec{v} + 2\vec{w} = \vec{0}. \]
What does this say about the set \( \{ \vec{u}, \vec{v}, \vec{w} \} \)?
**Answer:**
- There is not enough information to determine whether the set is linearly independent or linearly dependent.
- It is linearly independent.
- It is linearly dependent.
**Explanation:**
The equation provided is:
\[ -3\vec{u} + 5\vec{v} + 2\vec{w} = \vec{0}. \]
This represents a linear combination of vectors \( \vec{u} \), \( \vec{v} \), and \( \vec{w} \) resulting in the zero vector. The coefficients \(-3\), \(5\), and \(2\) are non-zero, indicating that a non-trivial linear combination of the vectors results in the zero vector. Therefore, the vectors \( \vec{u} \), \( \vec{v} \), and \( \vec{w} \) are linearly dependent.
_Selecting the correct answer:_
- It is linearly dependent.
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