Suppose for vectors u, v and w that – 3u + 5v + 2w = 0. What does this say about the set {u, v, w}? Answer: There is not enough information to determine whether the set is linearly independent or linearly dependent. O It is linearly independent It is linearly dependent

Algebra and Trigonometry (6th Edition)
6th Edition
ISBN:9780134463216
Author:Robert F. Blitzer
Publisher:Robert F. Blitzer
ChapterP: Prerequisites: Fundamental Concepts Of Algebra
Section: Chapter Questions
Problem 1MCCP: In Exercises 1-25, simplify the given expression or perform the indicated operation (and simplify,...
icon
Related questions
Question
### Linear Independence of Vectors

**Problem Statement:**

Suppose for vectors \( \vec{u} \), \( \vec{v} \), and \( \vec{w} \) that 

\[ -3\vec{u} + 5\vec{v} + 2\vec{w} = \vec{0}. \]

What does this say about the set \( \{ \vec{u}, \vec{v}, \vec{w} \} \)?

**Answer:**
- There is not enough information to determine whether the set is linearly independent or linearly dependent.
- It is linearly independent.
- It is linearly dependent.

**Explanation:**

The equation provided is:

\[ -3\vec{u} + 5\vec{v} + 2\vec{w} = \vec{0}. \]

This represents a linear combination of vectors \( \vec{u} \), \( \vec{v} \), and \( \vec{w} \) resulting in the zero vector. The coefficients \(-3\), \(5\), and \(2\) are non-zero, indicating that a non-trivial linear combination of the vectors results in the zero vector. Therefore, the vectors \( \vec{u} \), \( \vec{v} \), and \( \vec{w} \) are linearly dependent.

_Selecting the correct answer:_

- It is linearly dependent.
Transcribed Image Text:### Linear Independence of Vectors **Problem Statement:** Suppose for vectors \( \vec{u} \), \( \vec{v} \), and \( \vec{w} \) that \[ -3\vec{u} + 5\vec{v} + 2\vec{w} = \vec{0}. \] What does this say about the set \( \{ \vec{u}, \vec{v}, \vec{w} \} \)? **Answer:** - There is not enough information to determine whether the set is linearly independent or linearly dependent. - It is linearly independent. - It is linearly dependent. **Explanation:** The equation provided is: \[ -3\vec{u} + 5\vec{v} + 2\vec{w} = \vec{0}. \] This represents a linear combination of vectors \( \vec{u} \), \( \vec{v} \), and \( \vec{w} \) resulting in the zero vector. The coefficients \(-3\), \(5\), and \(2\) are non-zero, indicating that a non-trivial linear combination of the vectors results in the zero vector. Therefore, the vectors \( \vec{u} \), \( \vec{v} \), and \( \vec{w} \) are linearly dependent. _Selecting the correct answer:_ - It is linearly dependent.
Expert Solution
trending now

Trending now

This is a popular solution!

steps

Step by step

Solved in 2 steps with 2 images

Blurred answer
Knowledge Booster
Vector Space
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, algebra and related others by exploring similar questions and additional content below.
Similar questions
Recommended textbooks for you
Algebra and Trigonometry (6th Edition)
Algebra and Trigonometry (6th Edition)
Algebra
ISBN:
9780134463216
Author:
Robert F. Blitzer
Publisher:
PEARSON
Contemporary Abstract Algebra
Contemporary Abstract Algebra
Algebra
ISBN:
9781305657960
Author:
Joseph Gallian
Publisher:
Cengage Learning
Linear Algebra: A Modern Introduction
Linear Algebra: A Modern Introduction
Algebra
ISBN:
9781285463247
Author:
David Poole
Publisher:
Cengage Learning
Algebra And Trigonometry (11th Edition)
Algebra And Trigonometry (11th Edition)
Algebra
ISBN:
9780135163078
Author:
Michael Sullivan
Publisher:
PEARSON
Introduction to Linear Algebra, Fifth Edition
Introduction to Linear Algebra, Fifth Edition
Algebra
ISBN:
9780980232776
Author:
Gilbert Strang
Publisher:
Wellesley-Cambridge Press
College Algebra (Collegiate Math)
College Algebra (Collegiate Math)
Algebra
ISBN:
9780077836344
Author:
Julie Miller, Donna Gerken
Publisher:
McGraw-Hill Education