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Suppose first that a > 2. b) If æ > 2, then |æ – 2| = x-2 FORMATTING: Your answer should not have an absolute value. Therefore, when a > 2 we may simplify the expression for g(a) to get 9(x) = x+2 Hence, lim g(x) = 4 a2+ Suppose now that a < 2. c) If a < 2, then |æ – 2| = 2-x FORMATTING: Your answer should not have an absolute value. Therefore, when a < 2 we may simplify the expression for g(x) to get 9(2) = -(x+2) Hence, lim g(æ) = -4 d) Using (b) and (c) we conclude lim g(x)% = FORMATTING: if the limit doesn't exist write diverges.

Suppose first that a > 2. b) If æ > 2, then |æ – 2| = x-2 FORMATTING: Your answer should not have an absolute value. Therefore, when a > 2 we may simplify the expression for g(a) to get 9(x) = x+2 Hence, lim g(x) = 4 a2+ Suppose now that a < 2. c) If a < 2, then |æ – 2| = 2-x FORMATTING: Your answer should not have an absolute value. Therefore, when a < 2 we may simplify the expression for g(x) to get 9(2) = -(x+2) Hence, lim g(æ) = -4 d) Using (b) and (c) we conclude lim g(x)% = FORMATTING: if the limit doesn't exist write diverges.

Advanced Engineering Mathematics
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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Suppose first that a > 2. b) If æ > 2, then |æ – 2| = x-2 FORMATTING: Your answer should not have an absolute value. Therefore, when a > 2 we may simplify the expression for g(a) to get 9(x) = x+2 Hence, lim g(x) = 4 -2+ Suppose now that a < 2. c) If a < 2, then |æ – 2| = 2-x FORMATTING: Your answer should not have an absolute value. Therefore, when a < 2 we may simplify the expression for g(x) to get 9(x) = -(x+2) Hence, lim g(æ) = -4 d) Using (b) and (c) we conclude lim g(x) = FORMATTING: if the limit doesn't exist write diverges.
Transcribed Image Text:Suppose first that a > 2. b) If æ > 2, then |æ – 2| = x-2 FORMATTING: Your answer should not have an absolute value. Therefore, when a > 2 we may simplify the expression for g(a) to get 9(x) = x+2 Hence, lim g(x) = 4 -2+ Suppose now that a < 2. c) If a < 2, then |æ – 2| = 2-x FORMATTING: Your answer should not have an absolute value. Therefore, when a < 2 we may simplify the expression for g(x) to get 9(x) = -(x+2) Hence, lim g(æ) = -4 d) Using (b) and (c) we conclude lim g(x) = FORMATTING: if the limit doesn't exist write diverges.
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