Suppose f (x) =5"sec2(5*). Evaluate: tan (5*) + C In (5) (A) 5*. tan (5) B +C In (5) In (5) · tan (5*) +C (D 5*. In (5) - tan(5*)+C

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A:

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A: Since you have asked multiple questions in a single request we would be answering only the first…

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A: cos(2x ) =cos2(x)-sin2(x) = 2cos2(x)-1 =1-2sin2(x) sin(2x) = 2sin(x) cos(x)

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A: 1) f(x)=3 sinx cosx 2) f(x)=8cosx+6tanx.

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A: I=∫tan3(x)sec2(x)dxsubstitute  tanx=udiffrentiatesex2xdx=du