Suppose f: R2 × R² × R² → R was a 3-linear form on R² such that Compute f '(8·0·8) - 0, f (8.0·8) –¹ = = 1 f f = 1 - ƒ (8· 8 · 9) ---ƒ (6·8·9) – · == -1, 1(8.8.8)-(8.8.8) −2 ƒ(6·8·4)--³ /(6·A·9) = ± f = -3, ƒ(2,3,4]). 1.
Suppose f: R2 × R² × R² → R was a 3-linear form on R² such that Compute f '(8·0·8) - 0, f (8.0·8) –¹ = = 1 f f = 1 - ƒ (8· 8 · 9) ---ƒ (6·8·9) – · == -1, 1(8.8.8)-(8.8.8) −2 ƒ(6·8·4)--³ /(6·A·9) = ± f = -3, ƒ(2,3,4]). 1.
Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter4: Polynomial And Rational Functions
Section4.4: Complex And Rational Zeros Of Polynomials
Problem 46E
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![Suppose f: R2 × R² × R² → R was a 3-linear form on R² such that
Compute
f
'(8·0·8) -
0,
f
(8.0·8) –¹
= = 1
f
ƒ (8· 8 · 9) --- ƒ (6·9·9) – ·
== -1,
f
= 1
-
1(8.8.8)-(8.8.8)
−2
ƒ(6·8·4)--³ /(6·A·9) = ±
f
= -3,
ƒ(2,3,4]).
1.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F4217e83c-b4b2-47da-9d7a-2d6031448fca%2Fdecdc02a-bab0-48cf-8136-0dfe89687ca5%2F2dsbubq_processed.png&w=3840&q=75)
Transcribed Image Text:Suppose f: R2 × R² × R² → R was a 3-linear form on R² such that
Compute
f
'(8·0·8) -
0,
f
(8.0·8) –¹
= = 1
f
ƒ (8· 8 · 9) --- ƒ (6·9·9) – ·
== -1,
f
= 1
-
1(8.8.8)-(8.8.8)
−2
ƒ(6·8·4)--³ /(6·A·9) = ±
f
= -3,
ƒ(2,3,4]).
1.
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