Suppose f: [0, 1] → R and g: [0, 1] → Rare such that for all x E (0, 1), we have f(x) = g(x). Suppose f is Riemann integrable. f Prove that g is Riemann integrable and integral from 0 to 1 of  f = integral from 0 to 1 g

Advanced Engineering Mathematics
10th Edition
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Author:Erwin Kreyszig
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Chapter2: Second-order Linear Odes
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Can someone please rewrite this proof? The question is below: 

Suppose f: [0, 1] → R and g: [0, 1] → Rare such that for all x E (0, 1), we have f(x) = g(x). Suppose f is Riemann integrable. f Prove that g is Riemann integrable and integral from 0 to 1 of  f = integral from 0 to 1 g 

det
sum,
m
n mbintenab
M-1
nd, 1} and consider the right Riemann
ni
n
R₁ = = f(h)
1=1
== O
Now,
2
{ 0, h = 1,...,
n/
partition [0,1] inta
Hence,
Lince,
f, no,
and,
-
since, him. Premann integrable
1
Show da = lim Rn = 0
b
ma
= 0
h in Riemann integrable
f-h is also Riemann integrable
Sit-us
=
on [0, 1],
St
on
S's - S'u
f
h
0
in Riemann integrable on
S'o = 1/s
0
[0,1] and no is
on [0,1]
[0, 1] and
Transcribed Image Text:det sum, m n mbintenab M-1 nd, 1} and consider the right Riemann ni n R₁ = = f(h) 1=1 == O Now, 2 { 0, h = 1,..., n/ partition [0,1] inta Hence, Lince, f, no, and, - since, him. Premann integrable 1 Show da = lim Rn = 0 b ma = 0 h in Riemann integrable f-h is also Riemann integrable Sit-us = on [0, 1], St on S's - S'u f h 0 in Riemann integrable on S'o = 1/s 0 [0,1] and no is on [0,1] [0, 1] and
Let, hi [0, 1] → R defined by h(x) = fexs-g(x) *x.
Then, hex) = { 0, KE (0,1]
fco)-g(0), x = 0
Hence or in discontinuous on
fraint in [0,1].
Hence, using Lebesgue's Integrability Criterion hi
Riemann integrable on [0, 1].
atmast
one
Transcribed Image Text:Let, hi [0, 1] → R defined by h(x) = fexs-g(x) *x. Then, hex) = { 0, KE (0,1] fco)-g(0), x = 0 Hence or in discontinuous on fraint in [0,1]. Hence, using Lebesgue's Integrability Criterion hi Riemann integrable on [0, 1]. atmast one
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