Suppose E(X) = 1, V(X) = 2, E(Y)= 3, V(Y) = 4, and E(XY)= 5. (1) Сov (X, Y) (2) Corr(X,Y) (3) Cov(-6X +7, 8Y – 9)

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A: see below the calculation and answer

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Q: 2) z(x, y) = (x² + 5y)³ (3y + 2x)

A: Let's find dz/dx and dz/dy.

Q: If Var(X) = 4, Var(Y) = 16, Cov(X,Y) = 3, and E(X) = E(Y) = 0, what is E(XY)? Enter the exact…

A: Var(X)=4 Var(Y)=16 Cov(X,Y)=3 E(X)=E(Y)=0

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Q: Suppose E(X) = 2, V(X) = 4, E(Y) = 6, V (Y) = 8, and E(XY)= 10. (1) E(X +Y) (2) V(2X +3Y) (3) V (2X…

A: Since you have posted a question with multiple sub-parts, we will solve first three subparts for…

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Q: If Var(X+Y)=5, Var(X-Y)=2 and E(X)=1 and E(Y)=2 then Cov(X,Y)= (3/4 (1/4 (4/B

A: Thanks for the question :)And your upvote will be really appreciable ;)

Q: x² + y² = (3x² + 2y² – x)², (cardioid) 0, y 0.5 -0.5 0.5 1 -0.5

A: Giv:    x2 + y2 = ( 3x2 + 2y2 x )2     Point: ( 0 , 1/2 )

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A: Solution :-

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A: Find the derivative

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A: We can find the answer as below

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Q: 1) Find whether the signals are memoryless or memory? a) y(t) = 5x2(t+2) b) w(t) = (t-9)x(t)

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