Suppose data collected by observers at randomly selected intersections across the country revealed that in a sample of 100 drivers, 76 were using their cell phone.a. Give a point estimate of p, the true driver cell phone use rate (that is, the true proportion of drivers who are using their cell phone while driving).A point estimate for p is .b. Compute a 90% confidence interval for p.The 90% confidence interval for p is ( ).(Round to two decimal places as needed.)

Answered: Image /qna-images/answer/87510b6a-8ce9-42f7-91f4-bf27e1de8822.jpg

Answered: Suppose data collected by observers at…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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A research center survey of 2,484 adults found that 1,942 had bought something online. Of these online shoppers, 1,295 are weekly online shoppers. Complete parts (a) through (c) below. a. Construct a 95% confidence interval estimate of the population proportion of adults who had bought something online. Sas (Round to four decimal places as needed.) led b. Construct a 95% confidence interval estimate of the population proportion of online shoppers who are weekly online shoppers. Sas (Round to four decimal places as needed.) c. How would the director of e-commerce sales for a company use the results of (a) and (b)? O A. Since a greater proportion of adults have purchased something online than are weekly online shoppers, the director of e-commerce sales may want to focus on those adults who have purchased something online. led O B. The information cannot be compared because it is derived from two different opinions. O C. Agreater proportion of adults have purchased something online, but…
10. Which one of the following statements about confidence intervals is false? A. Given the same sample of data, a 90% confidence interval will be narrower than a 95% confidence interval. B. The size of the population does not affect the width of a confidence interval. C. The population proportion determines the center of the confidence interval. D. The value of z* affects the width of a confidence interval. E. The general format of a confidence interval is “sample statistic ± margin of error.”
If you want to be confident in your estimation of a confidence interval, you should use….
In a survey of 3444 adults aged 57 through 85 years, it was found that 85.9% of them used at least one prescription medication. Complete parts (a) through (c) below. a. How many of the 3444subjects used at least one prescription medication?=2958 (this was the correct answer.) b. Construct a 90% confidence interval estimate of the percentage of adults aged 57 through 85 years who use at least one prescription medication. 86.3%<p<88.1% (INCORRECT answer i got when i asked earlier) c. What do the results tell us about the proportion of college students who use at least one prescription medication? A. The results tell us that, with 90% confidence, the probability that a college student uses at least one prescription medication is in the interval found in part (b). or B. The results tell us that there is a 90% probability that the true proportion of college students who use at least one prescription medication is in the interval found in part (b). or C. The…
You want to estimate the average difference in the number of complaints filed by women at work and the number of complaints filed by men at work. You took an SRS of 7 businesses and collected the following data for number of complaints in a year: men 1 3 2 4 6 3 5 women 8 7 6 3 5 12 15 Create a 90% confidence interval for the average difference in the number of complaints filed by women at work and the number of complaints filed by men at work (in a year). You must do this using table C. If this is a 2 sample interval, be sure to specify who is population 1 and who is population 2. If this is a matched pairs interval, be sure to state the order you subtracted your data. Once you create your interval, give a sentence explaining the meaning of the interval (what the numbers in the interval mean, NOT the meaning of 95%) in context of this problem. Round to any appropriate number of decimals.
Assume that the 95% confidence interval for mean=9 and standard devaition=20. For a particular data, the standardized value z = 2.73. We can say that: Select one: a. The data with standardized value 2.73 does not belong to the confidence interval and the value is less than the average. b. The data with standardized value 2.73 does not belong to the confidence interval and the value is greater than the average. c. Cannot interpret the z-value information provided. d. The data with standardized value 2.73 if it belongs to the confidence interval and the value is less than the average. e. The data with standardized value 2.73 if it belongs to the confidence interval and the value is greater than the average.
A survey of 32,782 adults in 2004 indicated that 24.6% of adults were current smokers. A similar study conducted in 1995 of 40,000 adults indicated that 29.7% were current smokers. a. Find and interpret a point estimate of the difference between the proportion of current smokers in 1995, and the proportion of current smokers in 2004. b. A 95% confidence interval for the true difference is (-0.058,-0.045). Interpret. c. What assumptions must you make for the confidence interval i part b to be valid? (…) a. Find a point estimate of the difference between the proportion of current smokers in 1995 and the proportion of current smokers in 2004. (Round to three decimal places as needed.)
Suppose a researcher takes a random sample of 1,000 students from a university and creates a 95% confidence interval for the true proportion of left handed students at the university. Which of the following is true about this interval when compared with a 95% confidence interval based on a random sample of 600 students from the same university? a. The interval based on a sample of 600 students will be wider than the interval based on a sample of 1,000 students. b. The lower and upper endpoints of the 95% CI based on 600 students will both be larger than the corresponding lower and upper endpoints of the 95% CI based on 1,000 students. c. 95% CIs based in samples of 1,000 students are more likely to include the true population proportion than 95% CIs based on samples of 600 students. d. The interval based on a 1,000 students will be wider than the interval based on 600 students. 2. If the researchers above wished to decrease the width of the mean confidence interval for the mean age…
In a sample of 100 college students, 25 of them own a car. Calculate the 95% confidence interval for the true population of college students who own a car. Choose the closest one. A. (0.165132, 0.334868) B. (0.231725, 0.452302) C. (0.25, 0.75) D. (0.1, 0.9)
The following is the number of hours of sleep obtained by eight college freshmen. Use the data to find a 92% confidence interval for the true mean number of hours of sleep by college freshmen. 7.5 8.0 6.5 24 8.5 6.5 7.0 7.5
At a large high school, an assistant principal wants to know how intelligent the students at the school are. An intelligence test is administered to an SRS of 50 students, out of over 2000 students. The mean score was 115 and the standard deviation was 15. Construct a 99% confidence interval for the mean score of all students in the school. A) (109.32, 120.69) B) (119.58, 123.50) C) (110.87, 129.41) D) Can not be determined from the information given.

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