Suppose data about the average number of hours people spend on social media websites at work israndomly collected for 5 days: 5.1 4.8 2.5 4.3 2.4 If we assume this population is normally distributed, construct an 99% confidence interval for the population average amount of time people spend on social media websites at work.Suppose I want to know more about how workers spend their time throughout the day. I want to find evidence to disprove the claim that people spend less than 3 hours a day (during their workday) on social media. Test this claim (significance level =0.10). Do not use Excel

Data X 5.1 4.8 2.5 4.3 2.4 We have to find 1..construct an 99% confidence interval for the…

Answered: Suppose data about the average number…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Suppose data about the average number of hours people spend on social media websites at work is

randomly collected for 5 days:

5.1 4.8 2.5 4.3 2.4

If we assume this population is normally distributed, construct an 99% confidence interval for the population average amount of time people spend on social media websites at work.
Suppose I want to know more about how workers spend their time throughout the day. I want to find evidence to disprove the claim that people spend less than 3 hours a day (during their workday) on social media. Test this claim (significance level =0.10).

Do not use Excel

Features Features Normal distribution is characterized by two parameters, mean (µ) and standard deviation (σ). When graphed, the mean represents the center of the bell curve and the graph is perfectly symmetric about the center. The mean, median, and mode are all equal for a normal distribution. The standard deviation measures the data's spread from the center. The higher the standard deviation, the more the data is spread out and the flatter the bell curve looks. Variance is another commonly used measure of the spread of the distribution and is equal to the square of the standard deviation.

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