Suppose color blindness is a X linked trait in humans. It is also recessive. A phenotypically normal woman has a father with color blindness. This woman marries a man with normal vision. What is the chance of their children being color blind? What is the chance of their daughters being color blind?
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3. Suppose color blindness is a X linked trait in humans. It is also recessive. A
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- 5. Brown eyes are dominant over blue. This is NOT a sex-linked trait. If a blue-eyed colorblind woman marries a normal visioned man who is homozygous for brown eye color, what kind of children might they expect with respect to these two traits? If one of the sons in turn marries a heterozygous brown-eyed, normal visioned woman, not a carrier, what kinds of children might they expect? A normal woman who is a carrier for colorblindness marries a normal man. What types of offspring would you expect? 6. 100% Give Feedt4. Brown eyes are dominant over blue eyes. This is NOTA sex-linked trait. Cross a brown-eyed colorblind male (whose mother had blue eyes) with a normal blue-eyed female (whose father was colorblind). Genotype of the male Genotype of the female Genotypes Phenotypes What is the probability of getting offspring that are blue-eyed carrier females? (Remember that a carrier is a female that carries one copy of the sex-linked allele, but does not have the disease.) What is the probability of getting offspring that are blue-eyed? What is the probability of getting offspring that are blue-eyed colorblind males? What is the probability of getting offspring that are brown-eyed carrier females? What is the probability of getting offspring that are blue-eyed normal males? What is the probability of getting offspring that are colorblind?2. Can a color-blind female have a son that has normal vision? Color blindness is caused by a sex-linked recessive allele. Explain. Do the Punnett square. *use N = normal vision and n = color blind over X and Y chromosomes. 3. Muscular dystrophy is a sex-linked trait. What parental genotypes could produce a female with=muscular dystrophy? Do the Punnett square. *use M = normal muscles, and m = muscles missing dystrophin protein over X and Y chromosomes. 4. In humans, red-green color-blindness is due to a recessive gene X^c. Normal vision results from the dominant gene X^c. If a homozygous woman of normal vision marries a color-blind man, what type of vision will be expected in their children?
- 9. Red-green color blindness is inherited as an X-linked recessive (Xc). If a color-blind man marries a woman who is heterozygous for normal vision, what would be the expected phenotypes of their children with reference to this character? In your answer, specify in your phenotype descriptions the gender of the children. (For example, don’t just say 75% of the children would be colorblind – you would instead say 100 % of the daughters would be colorblind and 50% of the sons would be colorblind. Note that this is not a correct answer; it is just to give you an idea of how to explain the correct phenotypes of the cross.)___1. In man, normal color vision vs. red green colorblindness is controlled by C (dominant) and c (recessive) at an X-linked locus. a. Can a normal daughter have a color-blind father? A normal father? A color-blind mother? A normal mother? b. Can two normal parents have a color-blind son? A color-blind daughter? c. Can two color-blind parents have a normal daughter? A normal son?1. If one parent is homozygous dominant for a trait, that parent's genotype might be GG. If the other parent is homozygous recessive for the same trait, that parent's genotype would be gg. What are the possible genotypes of their offspring? b. How many different phenotypes might we possibly see in their offspring? 2. If a male is homozygous dominant for a trait, that parent's genotype might be DD. If the female is heterozygous for the same trait, her genotype would be Dd. a. How many genetically different sperm can the male produce? b. Using a Punnett square, determine the expected genotypic ratios of their offspring. What are the expected phenotypic ratios? 3. In garden peas, the gene for red flowers (R) is dominant over the gene for white flowers (r). If pollen (cells containing sperm nuclei) from the anther (male reproductive organ) of a homozygous red-flowered plant is added to the pistil (female reproductive organ containing the egg) of a white- flowered plant: a. c. What would be…
- 1. Red-green color blindness is an X-linked recessive trait in humans. Polydactyly (extra fingers and toes) is an autosomal dominant trait. Martha has normal fingers and toes and normal color vision. Her mother is normal in all respects, but her father is color blind and polydactylous. Bill is color blind and polydactylous. His mother has normal color vision and normal fingers and toes. Bill and Martha are married and about to have a child. a. Draw out a pedigree for all people mentioned in this problem. Fill in the left side of the box for anybody who is colorblind and fill in the right side of the box for anybody who is polydactyl. b. Determine the genotypes of Bill and Martha (it should look something like XBYDD) c. What is the probability that they will have a colorblind son with normal fingers?1. Muscular dystrophy is an x linked recessive disorder. If two of the four offsprings have muscular dystrophy and the other two are normal, predict the genotype of the parents. The offsprins are all boys and the parents appear normal. 2. At age 50, the girl is bald and the boy is not bald. They are twins. What is the genotype of the girl? Predict the genotype of the parents of the twins.7. A boy born with colour blindness has a dad who is colour blind but his mom is not. He is most likely to have gained the sex-linked allele of colour blindness from: a maternal relative only the allele is most likely a spontaneous mutation and was not inherited either a paternal or maternal relative a paternal relative only
- 1.In humans, one type of red-green color blindness is a sex-linked recessive. Normal color vision is dominant to color blindness. a. Two parents with normal vision produce a colorblind son. What are the genotypes of the parents? heterozygous for x-1inked trait mother IS carrier i father XY ANX is normal b. What are the chances of their next child being a colorblind female? c. What are the chances of their next child being a son with normal vision?1. Red-green colorblindness is caused by a recessive allele (x) at an X-linked gene, and albinism is caused by a recessive allele (a) at an autosomal gene. A phenotypically normal woman (Sara) has a father who is colorblind, and she knows that she is a carrier for albinism. She plans to have a child with a colorblind man (Abdul) who is also a carrier for albinism. What is the probability that Sara and Abdul's child will have one of the conditions, but not both? (C. Follow the steps below to answer this question. a) What is the cross? b) What are the target genotypes? Note: it might be useful to come back to this one and double- check it after you have completed step c, below. Break this down to the single gene level by answering the following questions: a. What is the proportion of normal to albino offspring? Show the Punnett square: b. What is the proportion of normal to colorblind offspring? Show the Punnett square: d) What is the probability that Sara and Abdul's child will have one…6. In cats, short hair, tabby, and normal (no colorpoint) are dominant traits. Long hair, no stripes, and colorpoint are recessive. Cross a homozygous short haired, homozygous colorpoint cat with a homozygous long haired, heterozygous normal cat. X (parent 1) (parent 2)