Suppose an array sorted in ascending order is rotated at some pivot unknown to you beforehand. (i.e., 0 1 2 4 5 6 7 might become 4 5 6 7 0 1 2). Find the minimum element. The complexity must be O(logN) You may assume no duplicate exists in the array. """ def find_min_rotate(array): """ Finds the minimum element in a sorted array that has been rotated. """ low = 0 high = len(array) - 1 while low < high: mid = (low + high) // 2 if array[mid] > array[high]: low = mid + 1 else: high = mid return array[low] def find_min_rotate_recur(array, low, high): """ Finds the minimum element in a sorted array that has been rotated. """ mid = (low + high) // 2 if mid == low:.
Suppose an array sorted in ascending order is rotated at some pivot unknown
to you beforehand. (i.e., 0 1 2 4 5 6 7 might become 4 5 6 7 0 1 2).
Find the minimum element. The complexity must be O(logN)
You may assume no duplicate exists in the array.
"""
def find_min_rotate(array):
"""
Finds the minimum element in a sorted array that has been rotated.
"""
low = 0
high = len(array) - 1
while low < high:
mid = (low + high) // 2
if array[mid] > array[high]:
low = mid + 1
else:
high = mid
return array[low]
def find_min_rotate_recur(array, low, high):
"""
Finds the minimum element in a sorted array that has been rotated.
"""
mid = (low + high) // 2
if mid == low:.
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