Suppose a stretched spring is used to supply power to a light bulb. The spring has a spring constant k=34.0 N/m and is stretched from its equilibrium length (which is the length where the spring force is zero) by a length 2.24 m. If the spring returns to its equilibrium length in 55.3 seconds, what is the average power in Watts that could be transferred from the spring to the light bulb?

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Chapter1: Units, Trigonometry. And Vectors
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Suppose a stretched spring is used to supply power to a light bulb. The spring has a spring constant k=34.0 N/m and is stretched from its equilibrium length (which is the length where the spring force is zero) by a length 2.24 m. If the spring returns to its equilibrium length in 55.3 seconds, what is the average power in Watts that could be transferred from the spring to the light bulb?

Expert Solution
Step 1

Given Data:

The magnitude of spring constant is, k=34.0 N/m

The extension in the spring is, x=2.24 m

The time taken by a spring to reach its equilibrium length is, t=55.3 s

 

The expression for the average power in terms of work done is given as,

P=Wt.................(1)

Here, W is the work done by the spring, and t is the time. 

 

The work done by a spring is calculated as,

W=12kx2W=12×34 N/m×2.24 m2W=85.29 J

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